菜单char输入到int

Question

我正在研究基于Tamagotchi的控制台（我不能画画，所以我正在使用我所拥有的）。对于我的菜单功能，我正在尝试提供菜单＆gt;将用户输入作为char＆gt;将char转换为int＆gt;进行选择。

#include <iostream>

//Functions
void menuShow();
int menuChoice();
void menuAction();

int main()
{
    menuAction();
}


//Menu display
void menuShow()
{
    std::cout << "\nPlease choose from the following:" << std::endl;
    std::cout << "(S)tatus of your pet." << std::endl;
    std::cout << "(F)eed your pet." << std::endl;
    std::cout << "(Q)uit." << std::endl;
}

//Convert input from char to int
int menuChoice()
{
    char userChoice;
    int convertChoice = 0;

    do
    {
        menuShow();
        std::cout << "Choice: ";
        std::cin >> userChoice;
        if ((userChoice = 'S') || (userChoice = 's'))
        {
            convertChoice = 1;
        }

        else if ((userChoice = 'F') || (userChoice = 'f'))
        {
            convertChoice = 2;
        }

        else if ((userChoice = 'Q') || (userChoice = 'q'))
        {
            convertChoice = 3;
        }

    } while ((userChoice != 'S') || (userChoice != 's') || (userChoice != 'F') || (userChoice != 'f') || (userChoice != 'Q') || (userChoice != 'q'));    //Repeat if incorrect selection is made

    return convertChoice;    //return converted int
}

//Get converted choice and perform related action
void menuAction()
{
    int choice;
    do
    {
        choice = menuChoice();    //initialize using returned convertChoice
        switch (choice)
        {
        case 1:
            std::cout << "You look at your pets' stats" << std::endl;
            break;

        case 2:
            std::cout << "You feed your pet" << std::endl;
            break;

        default:
            std::cout << "You have quit!" << std::endl;
            break;
        }
    } while (choice != 3);
}

截至目前，它不接受输入并执行操作，它只是一遍又一遍地吐出菜单。 所以我的问题是： 1）我是否在正确的轨道上进行转换工作，或者我甚至没有关闭？ 2）如果我离开了，你能把我推向正确的方向（鉴于这是可能的）吗？

另外，我知道这可以通过使用int来进行用户选择并传递给交换机来处理。但是，我想看看我是否可以这样做以备将来参考，并尝试在重复的“选项1：”，选项2：“等等方面考虑”开箱即用“。