Question

我想将一系列行转换为一系列列

create table #cusphone(cusid int,cusph1 int)
insert into #cusphone values(1,48509)
insert into #cusphone values(1,48508)
insert into #cusphone values(1,48507)
insert into #cusphone values(2,48100)

这样输出就像这样

            1 48509 48508 48507
            2 48100  null  null

Answer 1

您可以使用相同的rank（）方法，然后使用新的PIVOT函数，如下所示：

with    cusCte as(
select  cusid,cusph1,RANK() over (partition by cusid order by cusph1) r
from    #cusphone)

SELECT cusid, [1] AS C1, [2] AS C2, [3] AS C3
FROM 
(SELECT cusid,cusph1,r
FROM cusCte) p
PIVOT
(
MIN (cusph1)
FOR r IN
( [1], [2], [3] )
) AS pvt;

Answer 2

您没有指定在第一列和第二列中出现某些内容的规则，因此我猜测这是基于cusph1值的出现（以及排序）。

With RankedItems As
    (
    Select cusid, cusph1
        , ROW_NUMBER() OVER( PARTITION BY cusid ORDER BY cusph1 DESC) As Num
    From #cusphone
    )
Select cusid
    , Min(Case When Num = 1 Then cusph1 End) As Col1
    , Min(Case When Num = 2 Then cusph1 End) As Col2
    , Min(Case When Num = 3 Then cusph1 End) As Col3
From RankedItems
Group By cusid

行转换为sql 2008中的列

2 个答案: