Question

我试图总结所有时差差异值并以HH：mm：ss格式显示，但结果应该少于。

以下是我的DDL和我到目前为止的尝试：

CREATE TABLE tblproduction
    (
     OperaterID int,
     OperationID varchar(20), 
     StartDateTime datetime,
     EndDateTime datetime
    );

INSERT INTO `tblproduction` VALUES 
(227, 'OPEE21', '2014-12-01 05:51:34', '2014-12-01 06:48:30'),
(227, 'OPEE21', '2014-12-01 06:54:37', '2014-12-01 10:14:30'),
(227, 'OPEE21', '2014-12-01 10:23:03', '2014-12-01 13:41:31'),
(227, 'OPEE21', '2014-12-02 05:54:09', '2014-12-02 07:50:53'),
(227, 'OPEE21', '2014-12-02 07:55:03', '2014-12-02 13:37:56'),
(227, 'OPEE21', '2014-12-09 14:06:57', '2014-12-09 17:20:09'),
(227, 'OPEE21', '2014-12-09 17:22:07', '2014-12-09 21:51:24'),
(227, 'OPEE21', '2014-12-11 14:06:12', '2014-12-11 18:36:47'),
(227, 'OPEE21', '2014-12-12 14:07:09', '2014-12-12 14:58:42'),
(227, 'OPEE21', '2014-12-12 15:05:23', '2014-12-12 15:49:37'),
(227, 'OPEE21', '2014-12-12 15:55:12', '2014-12-12 21:55:24'),
(227, 'OPEE21', '2014-12-15 05:54:42', '2014-12-15 12:32:58'),
(227, 'OPEE21', '2014-12-15 12:38:48', '2014-12-15 13:40:08'),
(227, 'OPEE21', '2014-12-18 10:47:07', '2014-12-18 13:36:55'),
(227, 'OPEE21', '2014-12-19 06:16:58', '2014-12-19 13:37:29'),
(227, 'OPEE21', '2014-12-22 14:09:29', '2014-12-22 21:53:45'),
(227, 'OPEE21', '2014-12-23 14:26:54', '2014-12-23 17:12:13'),
(227, 'OPEE21', '2014-12-23 17:14:11', '2014-12-23 18:00:40'),
(227, 'OPEE21', '2014-12-23 18:03:51', '2014-12-23 21:07:57'),
(227, 'OPEE21', '2014-12-23 21:08:56', '2014-12-23 21:46:58');

SELECT p.OperaterID
     , p.OperationID
     , p.StartDateTime
     , p.EndDateTime
     , TIME_FORMAT(SUM(TIMEDIFF(p.EndDateTime, p.StartDateTime)), '%H:%i:%s') TotalTime
  FROM tblproduction p
 WHERE p.StartDateTime >= '2014-12-01 00:00:00' 
   AND p.StartDateTime <= '2014-12-31 23:59:59' 
   AND p.OperaterID = 227 
   AND p.OperationID = 'OPEE21'
 GROUP 
    BY p.OperationID;

+------------+-------------+---------------------+---------------------+-----------+
| OperaterID | OperationID | StartDateTime       | EndDateTime         | TotalTime |
+------------+-------------+---------------------+---------------------+-----------+
|        227 | OPEE21      | 2014-12-01 05:51:34 | 2014-12-01 06:48:30 | 63:48:44  |
+------------+-------------+---------------------+---------------------+-----------+

......还有一个相同的小提琴 SQL Fiddle

结果应为67:52:04，但查询返回63:48:44。我现在不会失去4个小时。

Answer 1

在TIMEDIFF结果上应用SUM。您应首先将TIMEDIFF转换为秒，而不是SUM，然后转换回来。

SELECT OperaterID, OperationID, 
StartDateTime, EndDateTime,
SEC_TO_TIME(SUM(TIME_TO_SEC(TIMEDIFF(tblproduction.EndDateTime, tblproduction.StartDateTime)))) AS TotalTime
FROM tblproduction
WHERE StartDateTime >= '2014-12-01 00:00:00' AND StartDateTime <= '2014-12-31 23:59:59' AND OperaterID = 227 AND OperationID = 'OPEE21'
GROUP BY OperationID;

Answer 2

这是一种方式......

SELECT operaterid
     , operationid
     , SEC_TO_TIME(SUM(TIME_TO_SEC(TIMEDIFF(EndDateTime,StartDateTime)))) total 
  FROM tblproduction 
 GROUP 
    BY operaterid
     , operationid;

所有timediff值的总和显示错误的值

2 个答案: