Question

我一直在寻找所有的互联网，但一直无法找到答案。也许我在寻找错误的东西。我正在尝试读取文本文件并让它更新GUI菜单栏。我所拥有的是：

$folder = Get-ChildItem $FilePath 
Foreach($file in $folder){
    $(Filename)= new-system System.Windows.Forms.ToolStripMenuItem
    $(filename).Name = "$(filename)"
    $(filename).Size = new-object System.Drawing.Size(35, 20)
    $(filename).Text = "&(filename)"
    $(foldername).item.add($(Name of file))
    $var = get-content c:\test\$file
    foreach($line in $var){
        $A = $line.split("^")
        $(Name of object) = new-system System.Windows.Forms.ToolStripMenuItem
        $(Name of object).Name = "$a[0]"
        $(Name of object).Size = new-object System.Drawing.Size(35, 20)
        $(Name of object).Text = "&$a[1]"
        $(FileName).item.add($(Name of object))

如何让它为文件及其中的每一行创建不同的变量名？我希望我的要求足够清楚。每个文件不会有超过20行读取。

Answer 1

$var = get-content c:\test\links.txt
foreach($line in $var){
$A = $line.split("^")
$variablename = "$"+ "var0"+ $a[0]
$createObject = "$Variablename = new-object system.windows.forms.toolstripmenuitem"
$settext = "$variablename.text = $a[0]"
$setsize = "$variablename.size = new-object System.drawing.size(35,20)"
$addmenu = "$ToolStripMenuItem.item.add($variablename)"
Invoke-expression $createObject 
Invoke-expression $settext
Invoke-expression $setsize
Invoke-expression $addmenu
}

Powershell使用test.txt中的值创建gui对象

1 个答案: