Question

我正在编写一个代码，允许我在我的数据库中保存用户查看页面的时间，当他点击＆＃34;关闭＆＃34;按钮，通过AJAX我在php页面上发布了一些参数，插入到DB（Mysql）中。

这是我的代码：

window.php（我正在浏览的页面）

<?php $start_time = microtime(true); 
?>

*page content*

<div align="center"><input type="button" value="Close" onclick="open()"></div>

<script language="javascript" type="text/javascript"> 
function open()
{
var start = <?php echo $start_time; ?>;
var end = <?php echo $end = microtime(true); ?>;
var uid = <?php echo $_SESSION['uid']; ?>;
var corso = <?php echo $_SESSION['cod']; ?>;
$.ajax({
  url: "http://www.mysite.it/template/pages/save.php",
  type: "POST",
  data: "startt="+start+"&endt="+end+"&uid="+uid+"&corso="+corso,

  success: function(){ // trigger when request was successfull
     alert("Recorded!");
  },

})

}


</script>

然后我的php脚本页面：

save.php

<?php
require "connection.php";

$inizio = $_POST['startt'];
$fine = $_POST['endt'];
$uid = $_POST['uid'];
$corso = $_POST['corso'];
$duration = $fine-$inizio;
$hours = (int)($duration/60/60);
$minutes = (int)($duration/60)-$hours*60;
$seconds = (int)$duration-$hours*60*60-$minutes*60;

$stringa = ($hours .":" .$minutes .":" .$seconds);
$sql = "INSERT INTO visua (utente, corso, tempo)
VALUES ($stringa, $uid, $corso)";
$result = $link->mysql_query($sql);
if ($result) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $link->error;
}

$link->close();

?>

实际上无法理解为什么不工作，即使＆＃34;成功＆＃34; AJAX的一部分显示消息，但DB上没有新行

谢谢你的建议。

Answer 1

<script language="javascript" type="text/javascript"> 
function open()
{
  var start = '<?php echo $start_time; ?>';
  var end = '<?php echo $end = microtime(true); ?>';
  var uid = '<?php echo $_SESSION['uid']; ?>';
  var corso = '<?php echo $_SESSION['cod']; ?>';
$.ajax({
  url: "http://www.mysite.it/template/pages/save.php",
  type: "POST",
  data: "startt="+start+"&endt="+end+"&uid="+uid+"&corso="+corso,

 success: function(){ // trigger when request was successfull
   alert("Recorded!");
},

})

}


</script>

Answer 2

   <?php
require "connection.php";

$inizio = $_POST['startt'];
$fine = $_POST['endt'];
$uid = $_POST['uid'];
$corso = $_POST['corso'];
$duration = $fine-$inizio;
$hours = (int)($duration/60/60);
$minutes = (int)($duration/60)-$hours*60;
$seconds = (int)$duration-$hours*60*60-$minutes*60;

$stringa = ($hours .":" .$minutes .":" .$seconds);
$sql = "INSERT INTO visua (utente, corso, tempo)
VALUES ('$stringa', '$uid', '$corso')";
$result = $link->mysql_query($sql);
if ($result) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $link->error;
}

$link->close();

?>

可能会起作用....在此之前你需要检查ajax值或传递或不传...

Answer 3

试试这段代码，

<script type="text/javascript">
function open(){
    var start = '<?php echo $start_time; ?>';
    var end = '<?php echo $end = microtime(true); ?>';
    var uid = '<?php echo $_SESSION['uid']; ?>';
    var corso = '<?php echo $_SESSION['cod']; ?>';
    $.ajax({
        url: "http://www.mysite.it/template/pages/save.php",
        type: "POST",
        data: {
            startt : start,
            endt : end,
            uid : uid,
            corso : corso
        },
        success: function(){ // trigger when request was successfull
            alert("Recorded!");
        }
    });
}
</script>

此外，这是一个可以帮助您的逻辑问题。如果您需要计算用户关闭页面的结束时间，请在 save.php 文件中计算结束时间，

<?php
$fine = microtime(true);

//Also try including single-quote in your query for insert
$sql = "INSERT INTO visua (utente, corso, tempo) VALUES ('$stringa', '$uid', '$corso')";
?>

这将为您提供预期的结果。

希望这有帮助!!!

为什么我的保存时间功能不起作用？ PHP + AJAX JS

3 个答案: