Question

我试图在Matlab2014b环境下以数字方式解决以下等式。但是matlab不输出数值解，而是输出以下

>>solve(1/beta(13,11)*x^(12)*(1-x)^(10)==1.8839,x)
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[1]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[1]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[2]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[2]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[3]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[3]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[4]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[4]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[5]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[5]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[6]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[6]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[7]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[7]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[8]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[8]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[9]
      RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[9]
     RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[10]
     RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[10]
     RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 - (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[11]
     RootOf(z^11 - 5*z^10 + 10*z^9 - 10*z^8 + 5*z^7 - z^6 + (4096*10^(1/2)*3342794185613871913^(1/2))/66540040320887625, z)[11]

另一方面，我没有用Wolframmath解决方程式的问题。我想知道导致问题的原因，可能值得注意的是，方程确实有复杂的解决方案，但我只对0和1之间的解决方案感兴趣。

Answer 1

我刚刚遇到同样的问题，我想我已经找到了解决方案。

根据我得到的信息，MATLAB可以在某个时候执行此操作，只是简单地表示分析解决方案。要评估解决方案，只需调用HttpContext.Current.Session.GetInt32("Template");函数即可。这是一个最小的复制和解决方案。

vpa

结果就像

    syms x
    solve(x^5 + x + 7)

只需尝试

    ans =

     RootOf(z^5 + z + 7, z)[1]
     RootOf(z^5 + z + 7, z)[2]
     RootOf(z^5 + z + 7, z)[3]
     RootOf(z^5 + z + 7, z)[4]
     RootOf(z^5 + z + 7, z)[5]

然后数字结果将显示：

    vpa(ans)

有关详细信息，请参阅MATLAB文档：

http://au.mathworks.com/help/symbolic/solve.html#zmw57dd0e111869

Matlab没有输出方程的数值解（而是输出“一些多项式的根”＆＃39;＆＃39;）

1 个答案: