Question

我的代码很少<asp:ImageButton>。但是当我按 Enter 键时我想做，而不是其他人改变但只有提交按钮有效。现在，当我在代码中按 Enter 键时，.calendar班级按钮正常工作并且日历出现。

jquery的

$('form').keypress(function (e) {
            if (e.which == 13) {
                $('.submit').submit();
                //return false;
            }
        });

的.aspx

<div id="form">
<div id="main">
    <div>
        <ul>
            <li>
                <asp:TextBox ID="txtDate1" runat="server" CssClass="textbox"></asp:TextBox>
                <asp:ImageButton ID="Button1" CssClass="calbutton" runat="server" OnClick="Button1_Click" Text="Show Calendar" AutoPostBack="True"/>
                <div class="calendar">
                    <asp:Calendar ID="Calendar1" runat="server" OnSelectionChanged="Calendar1_SelectionChanged" Visible="False">
                    </asp:Calendar>
                </div>
            </li>
            <li>
                <asp:ImageButton ID="ImageView" CssClass="submit" runat="server" onclick="ImageView_Click"  AutoPostBack="True" />
            </li>
        </ul>
    </div>

Answer 1

包装在asp：面板中并设置默认按钮。

Answer 2

这样的事情对你来说可能有用..：）

<强> HTML

<form id="myForm">
        <div id="main">
            <div>
                <ul>
                    <li>
                        <asp:TextBox ID="txtDate1" runat="server" CssClass="textbox"></asp:TextBox>
                        <asp:ImageButton ID="Button1" CssClass="calbutton" runat="server" OnClick="Button1_Click" Text="Show Calendar" AutoPostBack="True" />
                        <div class="calendar">
                            <asp:Calendar ID="Calendar1" runat="server" OnSelectionChanged="Calendar1_SelectionChanged" Visible="False"></asp:Calendar>
                        </div>
                    </li>
                    <li>
                        <asp:ImageButton ID="ImageView" CssClass="submit" runat="server" onclick="ImageView_Click" AutoPostBack="True" />
                    </li>
                </ul>
            </div>
        </div>
    </form>

<强>脚本

$('#myForm input').keypress(function (e) {
            if (e.which == 13) {
                $("#myForm").submit();
                return false;
            }
        });

按enter键刷新页面

2 个答案: