Question

我从How do I get a raw, compiled SQL query from a SQLAlchemy expression?获得了以下代码，它在我们从Python 2.7迁移到Python 3.4之前一直运行良好。我已经做了一些改变但是我坚持

return (comp.string.encode(enc) % params).decode(enc)

错误不支持操作数类型％：＆＃39; bytes＆＃39;和＆＃39; dict＆＃39;

def compile_query(query):
    dialect = query.session.bind.dialect
    statement = query.statement
    comp = compiler.SQLCompiler(dialect, statement)
    comp.compile()
    enc = dialect.encoding
    params = {}
    for k,v in comp.params.iteritems():
        if isinstance(v, unicode):
            v = v.encode(enc)
        params[k] = sqlescape(v)
    return (comp.string.encode(enc) % params).decode(enc)

Answer 1

感谢评论，我把它移植到python 3

def compile_query(query):
    dialect = query.session.bind.dialect
    statement = query.statement
    comp = compiler.SQLCompiler(dialect, statement)
    comp.compile()
    enc = dialect.encoding
    params = {}
    for k,v in comp.params.items():
        if isinstance(v, str):
            v = v.encode(enc)
        params[k] = sqlescape(v)
    return (comp.string % params)

python 2.7到python 3.4错误不支持的操作数类型为％：＆＃39; bytes＆＃39;和＆＃39; dict＆＃39;

1 个答案: