Question

我正在尝试从以特定模式开头的行中删除空格。所有其他线路都不会受到影响。例如

ODBC;    DSN=Orac         lePacket1;      DBA=W;     ;APA=R

应该是

ODBC;DSN=Oracle;DBA=W;APA=R

但

Table:     LPR_MONTH_VRNM_COM

应保持

Table:     LPR_MONTH_VRNM_COM

我虽然解决方案非常简单，但Notepad Plus中的正则表达式并不与我合作。

Answer 1

您可以使用此模式而不替换任何内容：

(?:\G(?!^)|^(?!Table:))[^ \n\r]*\K +

demo

模式细节：

(?:              # Two possible branches:

                 # A branch contiguous to the precedent match:
    \G           # anchor for the end of the last match or the start of the string
    (?!^)        # not at the start of the string (or the line)       

  |              # OR

    ^(?!Table:)  # A branch at the start of the line but not followed by "Table:"

)

                 # Then we reach the next space:
[^ \n\r]*        # all characters that are not a space or a newline

\K               # removes all that have been matched on the left from the result
[ ]+             # then only spaces will be removed.

尝试使用Notepad ++仅在某些行上删除空白

1 个答案: