Question

我有一个查询，它将测试的Pass / Fails每周的音量显示为两个单独的列。我想添加第三列，显示失败的百分比 - （1 /（失败+通过））*失败。

SELECT to_char(DATE,'YYYY'), to_char(DATE,'WW'), 
  SUM(case WHEN Result = 'Y' then 1 else 0 end) Failed, 
  SUM(case WHEN Result = 'N' then 1 else 0 end) Passed
FROM Result_table
GROUP BY to_char(DATE,'YYYY'), to_char(DATE,'WW')
ORDER BY to_char(DATE,'YYYY'), to_char(DATE,'WW');

我相信我必须使用上面的子查询（因此已经定义了Failed和Passed），但是，我不断收到错误 - 所以我不确定这是否是正确的方法。

非常感谢任何帮助。

干杯

Answer 1

要将其用作子查询，您需要将order by移动到外部查询，这意味着您需要年份和周列，因此要别名：

SELECT year_num, week_num, failed, passed,
  100 * failed / (failed + passed) as failed_percent
FROM (
  SELECT to_char(DATE,'YYYY') as year_num,
    to_char(DATE,'WW') as week_num, 
    SUM(case WHEN Result = 'Y' then 1 else 0 end) as failed, 
    SUM(case WHEN Result = 'N' then 1 else 0 end) as passed
  FROM Result_table
  GROUP BY to_char(DATE,'YYYY'), to_char(DATE,'WW')
)
ORDER BY year_num, week_num;

Oracle SQL - 显示新列中两列的百分比

1 个答案: