到目前为止,我们可以做到:
我们如何swipeTop(一直到顶部)或swipeBottom(一直到底部)是expresso。如果这些方法已经存在,请举个例子。
答案 0 :(得分:15)
您是否尝试过这样的GeneralSwipeAction
?
private static ViewAction swipeFromTopToBottom() {
return new GeneralSwipeAction(Swipe.FAST, GeneralLocation.TOP_CENTER,
GeneralLocation.BOTTOM_CENTER, Press.FINGER);
}
也许您必须为第二个和/或第三个参数提供自定义实现,正如Anna已经提到的那样:
new CoordinatesProvider() {
@Override
public float[] calculateCoordinates(View view) {
float[] coordinates = GeneralLocation.CENTER.calculateCoordinates(view);
coordinates[1] = 0;
return coordinates;
}
}
答案 1 :(得分:8)
例如,如果您在自己的应用程序中使用recyclerView,则可以使用以下内容:
Espresso.onView(ViewMatchers.withId(R.id.recyclerView)).perform(ViewActions.swipeUp())
或
Espresso.onView(ViewMatchers.withId(R.id.recyclerView)).perform(ViewActions.swipeDown())
答案 2 :(得分:4)
我认为可以通过执行滑动来编写复杂的ViewActions
来完成。
public static ViewAction swipeToTop() {
return new MySwipeAction(Swipe.FAST,
GeneralLocation.CENTER,
new CoordinatesProvider() {
@Override
public float[] calculateCoordinates(View view) {
float[] coordinates = GeneralLocation.CENTER.calculateCoordinates(view);
coordinates[1] = 0;
return coordinates;
}
}, Press.FINGER);
}
public static ViewAction swipeToBottom() {
return new MySwipeAction(Swipe.FAST,
GeneralLocation.CENTER,
new CoordinatesProvider() {
@Override
public float[] calculateCoordinates(View view) {
float[] coordinates = GeneralLocation.CENTER.calculateCoordinates(view);
coordinates[1] = view.getContext().getResources().getDisplayMetrics().heightPixels;
return coordinates;
}
}, Press.FINGER);
}
MySwipeAction可能是这样的:
public class MySwipeAction implements ViewAction {
public MySwipeAction(Swiper swiper, CoordinatesProvider startCoordProvide, CoordinatesProvider endCoordProvide, PrecisionDescriber precDesc) {
// store here in class variables to use in perform
...
}
@Override public Matcher<View> getConstraints() {...}
@Override public String getDescription() {...}
@Override
public void perform(UiController uiController, View view) {
...
float[] startCoord = startCoordProvide.calculateCoordinates(view);
float[] finalCoord = endCoordProvide.calculateCoordinates(view);
float[] precision = precDesc.describePrecision();
Swiper.Status status = Swiper.Status.FAILURE;
// you could try this for several times until Swiper.Status is achieved or try count is reached
try {
status = m_swiper.sendSwipe(uiController, startCoord, finalCoord, precision);
} catch (RuntimeException re) {
...
}
// ensures that the swipe has been run.
uiController.loopMainThreadForAtLeast(ViewConfiguration.getPressedStateDuration());
}
}
我希望这可以帮到你。
答案 3 :(得分:1)
@testsingh 我认为没有开箱即用的方法来做&#34; swipeTop&#34;或者&#34; swipeBottom&#34; 循环可能是最简单的方法(最愚蠢),对我来说是XDDD
// swipeUp 100次,反之亦然swipeDown
function checkNested(obj /*, level1, level2, ... levelN*/) {
var args = Array.prototype.slice.call(arguments, 1);
for (var i = 0; i < args.length; i++) {
if (!obj || !obj.hasOwnProperty(args[i])) {
return false;
}
obj = obj[args[i]];
}
return true;
}
var test = {level1:{level2:{level3:'level3'}} };
checkNested(test, 'level1', 'level2', 'level3'); // true
checkNested(test, 'level1', 'level2', 'foo'); // false
答案 4 :(得分:1)
我知道我迟到了,但经过一段时间的努力,我终于发现了一些可以从上到下,从左到右等方式进行扫描的东西,而且不需要任何资源ID。
我需要它的原因是一个动态填充的视图,其中一切都是完全不明确的。通过下面的方法,我可以一直滚动到底部,甚至可以更改延迟以向下滚动一页。
static void swiper(int start, int end, int delay) {
long downTime = SystemClock.uptimeMillis();
long eventTime = SystemClock.uptimeMillis();
Instrumentation inst = getInstrumentation();
MotionEvent event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_DOWN, 500, start, 0);
inst.sendPointerSync(event);
eventTime = SystemClock.uptimeMillis() + delay;
event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_MOVE, 500, end, 0);
inst.sendPointerSync(event);
event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_UP, 500, end, 0);
inst.sendPointerSync(event);
SystemClock.sleep(2000); //The wait is important to scroll
}
我不需要从左到右等,所以我在那里硬编码500(500是x轴)。
并且打电话给他们我做了它我做了 -
// This swipes all the way to the bottom of the screen
public static void swipeToBottom(){
swiper(1000, 100, 0);
}
// This scrolls down one page at a time
public static void scrollSlowlyDown(){
swiper(775, 100, 100);
}
// This swipes to the top
public static void swipeToTop(){
swiper(100, 1000, 0);
}
// This scrolls up one page at a time
public static void scrollSlowlyUp(){
swiper(100, 775, 100);
}
我希望这有助于任何绊倒这个的人。
答案 5 :(得分:1)
//向上滑动
for(int i=0;i<=3;i++){
onView(allOf(withId(R.id.recycler_view),isDisplayed())).perform(actionOnItemAtPosition(4, swipeUp()));
}
//向下滑动
for(int i=0;i<=3;i++){
onView(allOf(withId(R.id.recycler_view),isDisplayed())).perform(actionOnItemAtPosition(7, swipeDown()));
}