我试图收集复选框数据而不添加要提交的按钮。
这是我到目前为止的代码:
<!-- Web form -->
<form class="switcher-form" method="post">
<p class="setting-switch setting-switch-first">
<label for="setting1">Controle Total</label>
<!-- switcher checkbox #1 -->
<input type="checkbox" class="switcher" checked name="setting1" value="1" onclick="submit();"/>
</p>
<p class="setting-switch">
<label for="setting2">Controle Sala</label>
<!-- switcher checkbox #2 -->
<input type="checkbox" class="switcher" checked name="setting2" value="2" onclick="submit();"/>
</p>
<p class="setting-switch">
<label for="setting3">Controle Quarto A</label>
<!-- switcher checkbox #3 -->
<input type="checkbox" class="switcher" checked name="setting3" value="3" onclick="submit();"/>
</p>
<p class="setting-switch">
<label for="setting4">Controle Quarto B</label>
<!-- switcher checkbox #4 -->
<input type="checkbox" class="switcher" checked name="setting4" value="4" onclick="submit();"/>
</p>
<p class="setting-switch">
<label for="setting5">Controle Cozinha</label>
<!-- switcher checkbox #5 -->
<input type="checkbox" class="switcher" checked name="setting5" value="5" onclick="submit();"/>
</p>
<p class="setting-switch">
<label for="setting6">Controle Garagem</label>
<!-- switcher checkbox #6 -->
<input type="checkbox" class="switcher" checked name="setting6" value="6" onclick="submit();"/>
</p>
<p class="setting-switch">
<label for="setting7">Controle Portao</label>
<!-- switcher checkbox #7 -->
<input type="checkbox" class="switcher" checked name="setting7" value="7" onclick="submit();"/>
</p>
<p class="setting-switch">
<label for="setting8">Controle Refrigeracao</label>
<!-- switcher checkbox #8 -->
<input type="checkbox" class="switcher" checked name="setting8" value="8" onclick="submit();"/>
</p>
</form>
<!-- End: Web form -->
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是否可以使用POST或GET方法?自动发送复选框,例如:http://index.htm?setting1=0
我对CSS HTML JS不太满意,这段代码在微控制器上运行。
答案 0 :(得分:1)
听起来您想在复选框中添加onclick
事件,以便Javascript函数可以通过XMLHttpRequest
在后台联系服务器,如下所示:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Example</title>
</head>
<body>
<script>
"use strict"
function doAJAX()
{
console.log("Contacting the server...");
var xhr = new XMLHttpRequest();
xhr.onload = function()
{
console.log("Got a response!");
};
xhr.open("get", "http://localhost:3000/something.png", true);
xhr.responseType = "blob";
xhr.send();
}
</script>
<input type="checkbox" onclick="doAJAX();">
</body>
</html>
请注意,如果您要发送/接收其他域名,则可能需要考虑CORS。
答案 1 :(得分:0)