Question

我在列表中有三个句子：

sentences = []
sentence.append("This is my first sentence.")
sentence.append("This is my second sentence.")
sentence.append("This is my third sentence.")

我需要拆分它们，所以结果应该是： [['This'，'is'，'my'，'first'，'sentence。']， ['This'，'is'，'my'，'second'，'sentence。']， ['这'，'是'，'我'，'第三'，'句子。']]

我尝试按照以下方式分配一个新列表：

sentencesplit = []
for i in range(0, 3):
   sentencesplit.extend(sentence[i].split())

结果是包含句子中所有分割字符串的一维列表。我甚至试图宣布

sentencesplit[[]]
for i in range(0, 3):
   sentencesplit[i].extend(sentence[i].split())

但这只会导致错误消息列表索引超出范围。

知道如何解决这个问题吗？

Answer 1

[sentence.split(' ')  for sentence in sentences]

Answer 2

尝试使用“追加”：

sentencesplit = []
for i in range(0, 3):
   sentencesplit.append(sentence[i].split())

Answer 3

sentenceList = ["This is my first sentence.",
                "This is my second sentence.",
                "This is my third sentence."]
result = []
for i in range(len(sentenceList)):
    result.append(sentenceList[i].split(" "))

打印结果

[['This', 'is', 'my', 'first', 'sentence.'], 
 ['This', 'is', 'my', 'second', 'sentence.'], 
 ['This', 'is', 'my', 'third', 'sentence.']]

Answer 4

只需使用简单的map和lambda来制作列表：

>>> strs = ['This is an example','This is an example','This is an example']
>>> map(lambda split_str: split_str.split(' '), strs)
[['This', 'is', 'an', 'example'], ['This', 'is', 'an', 'example'], ['This', 'is', 'an', 'example']]

或没有lamdba：

>>> import string
>>> strs = ['This is an example','This is an example','This is an example']
>>> map(string.split, strs)
[['This', 'is', 'an', 'example'], ['This', 'is', 'an', 'example'], ['This', 'is', 'an', 'example']]

Answer 5

sentences = []
sentences.append("This is my first sentence.".split())
sentences.append("This is my second sentence.".split())
sentences.append("This is my third sentence.".split())

在追加之前拆分它们。

我想将字符串列表拆分为二维数组

5 个答案: