Question

我是CI的新手，我想知道如何从不同的模型中检索数据但是相同的视图。

我有2个模型，一个用于评估费用的细分，另一个是费用评估细目的总价格。

    function result_getAssessment($studentid)
            {

                $sql=
                "
                select g.studentid, sb.subjectcode, s.price
                FROM grades g
                INNER JOIN subjectblocking sb ON g.blockcode=sb.blockcode
                INNER JOIN subjects s ON sb.subjectcode=s.subjectcode
                WHERE studentid='$studentid'
                ";

                $result = $this->db->query($sql);
                $result = $result->result();
                return $result; 

            }

function result_totalAssessment($studentid)
        {
            $sql=
            "
            SELECT sum(s.numofunit) total_units, sum(s.price) total_tuition FROM subjects s
            INNER JOIN subjectblocking sb ON s.subjectcode=sb.subjectcode
            INNER JOIN grades g ON sb.blockcode=g.blockcode
            WHERE g.studentid='$studentid'
            ";

            $result = $this->db->query($sql);
            $result = $result->result();
            return $result; 
        }

我的控制器：

 function getAssessment() 
{
   $this->load->view('header');
   $this->load->view('navbar');
   $this->load->view('sidebar');
   $this->load->view('footer');
   $studentid = $this->session->userdata('studentid');
   $data['studentid'] = $studentid;
   $data['query'] = $this->m_login->result_getAssessment($studentid);
   $this->load->view('v_assessment',$data);
   $this->gettotalAssessment();
}

  function gettotalAssessment() 
{
   $studentid = $this->session->userdata('studentid');
   $data['studentid'] = $studentid;
   $data['query'] = $this->m_login->result_totalAssessment($studentid);
   $this->load->view('v_assessment',$data);
}

我的观点：

<?php foreach ($query as $row){ ?>

              <tr>
              <td> <?php echo $row->subjectcode;?> <br></td>
              <td> <?php echo $row->price;?><br></td>
              <td> <?php echo $row->total_tuition;?><br></td>
              </tr>
<?php } ?>

请帮助我，如何从两个模型中检索数据并从一个视图中显示它。提前谢谢！

Answer 1

codeigniter documentation中的这似乎微不足道。虽然我对codeigniter相对较新，但我的贡献可能很方便。在这里：确保加载两个模型（比如在控制器类构造函数中）。然后代码中有这两行导致问题

1. $data['query'] = $this->m_login->result_getAssessment($studentid); <<<found in getAssessment() method

和

2. $data['query'] = $this->m_login->result_totalAssessment($studentid); <<<found in  gettotalAssessment()  method

您必须为这些结果指定不同的数组键因为你在某种程度上动态地构建数组。见：php manual 另请注意，在指定现有索引时向数组添加alement时，该索引处的值将被新值覆盖。希望这会给你的解决方案搜索带来更多的肉体。

Answer 2

实际上，在控制器中加载$this->gettotalAssessment();中需要执行此操作的视图后，您正在调用getAssessment()函数

function getAssessment() 
{
   $this->load->view('header');
   $this->load->view('navbar');
   $this->load->view('sidebar');
   $this->load->view('footer');
   $studentid = $this->session->userdata('studentid');
   $data['studentid'] = $studentid;
   $data['query'] = $this->m_login->result_getAssessment($studentid);
   $data['totalAssessment'] = $this->m_login->result_totalAssessment($studentid);
   $this->load->view('v_assessment',$data);

}

在您的视图中，您可以通过

访问总评估

$totalAssessment

从codeigniter中的两个不同模型中检索数据并在一个视图中显示它

2 个答案: