我对正则表达式真的很陌生,但我认为我的问题可能会超出目前的范围。正如标题所说,我正在试图确定信用卡是签证,美国运通卡,万事达卡等。
我查看了这篇文章,其中给出了每种卡类型的正则表达式:
How do you detect Credit card type based on number?
这是我之后使用的代码,但它根本不做任何事情:
etCCNum.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
Log.d("DEBUG", "beforeTextChanged : "+s);
}
@Override
public void afterTextChanged(Editable s) {
Pattern pattern = Pattern.compile("^6(?:011|5[0-9]{2})[0-9]{3,}$");
Log.d("DEBUG", "afterTextChanged : "+s);
String ccNum = s.toString();
Matcher matcher = pattern.matcher(ccNum);
if(matcher.matches()){
Log.d("DEBUG", "afterTextChanged : discover");
}
}
});
pattern.compile函数中的regexp用于根据上面的帖子确定Discover卡。我注意到除了正则表达式中的“^”之外我真的无法工作(即(“^ 4” - 签证,“^ 6001”发现)但是在编辑时这显然是不够的例子。任何想法是什么?我认为这可能是我的Java的一个问题,但我正在运行Java 7
我可能想把它作为一个新问题,但我也想知道如何使用正则表达式来获得各种信用卡的间距,即使用户返回并编辑数字(xxxx xxxx xxxx xxxx)
编辑:从上面添加了DEBUG日志。我的输入是一些应该与某些信用卡相关联的数字。目前我正在使用下面提供的Eagle Eye代码(这也适用于检测输入是其中一种卡类型):
final ArrayList listOfPattern = new ArrayList();
String ptVisa = "^4[0-9]{6,}$";
listOfPattern.add(ptVisa);
String ptMasterCard = "^5[1-5][0-9]{5,}$";
listOfPattern.add(ptMasterCard);
String ptAmeExp = "^3[47][0-9]{5,}$";
listOfPattern.add(ptAmeExp);
String ptDinClb = "^3(?:0[0-5]|[68][0-9])[0-9]{4,}$";
listOfPattern.add(ptDinClb);
String ptDiscover = "^6(?:011|5[0-9]{2})[0-9]{3,}$";
listOfPattern.add(ptDiscover);
String ptJcb = "^(?:2131|1800|35[0-9]{3})[0-9]{3,}$";
listOfPattern.add(ptJcb);
etCCNum.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
Log.d("DEBUG", "beforeTextChanged : "+s);
}
@Override
public void afterTextChanged(Editable s) {
Log.d("DEBUG", "afterTextChanged : "+s);
String ccNum = s.toString();
for(String p:listOfPattern){
if(ccNum.matches(p)){
Log.d("DEBUG", "afterTextChanged : discover");
break;
}
}
}
});
日志:
01-29 15:16:41.932 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged :
01-29 15:16:41.933 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 4
01-29 15:16:46.815 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 4
01-29 15:16:46.816 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged :
01-29 15:16:50.925 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged :
01-29 15:16:50.926 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 6
01-29 15:16:51.542 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 6
01-29 15:16:51.543 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 60
01-29 15:16:51.883 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 60
01-29 15:16:51.883 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 600
01-29 15:16:52.928 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 600
01-29 15:16:52.929 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 6001
01-29 15:16:55.781 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 6001
01-29 15:16:55.782 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 600
01-29 15:16:56.206 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 600
01-29 15:16:56.206 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 60
01-29 15:16:57.659 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 60
01-29 15:16:57.660 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 605
01-29 15:16:59.297 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 605
01-29 15:16:59.298 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 60
01-29 15:16:59.527 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 60
01-29 15:16:59.527 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 6
01-29 15:17:00.314 26194-26194/com.x.x D/DEBUG﹕ beforeTextChanged : 6
01-29 15:17:00.314 26194-26194/com.x.x D/DEBUG﹕ afterTextChanged : 65
对于我输入的不同数字,您希望日志“发现”出现几次。上面的日志显示我输入了签证卡和发现卡的前几位数字。
编辑答案:我根本没有输入足够的数字来识别卡片!
答案 0 :(得分:16)
根据帖子中的一个答案,可以根据以下数据验证卡片。
签证: ^4[0-9]{6,}$
Visa卡号码以4开头。
万事达卡: ^5[1-5][0-9]{5,}$
万事达卡号码以数字51到55开头,但这只会检测万事达信用卡;使用万事达卡系统发行的其他卡不属于此IIN范围。
美国运通: ^3[47][0-9]{5,}$
美国运通卡号码以34或37开头。
大莱卡: ^3(?:0[0-5]|[68][0-9])[0-9]{4,}$
大莱卡的卡号从300到305,36或38开头。大莱卡的卡片以5开头,有16位数字。这些是大莱卡和万事达卡之间的合资企业,应该像万事达卡一样处理。
发现 ^6(?:011|5[0-9]{2})[0-9]{3,}$
发现卡号以6011或65开头。
JCB: ^(?:2131|1800|35[0-9]{3})[0-9]{3,}$
JCB卡以2131,1800或35开头。
因此,您需要为每个案例创建单独的模式。你可以这样做。
ArrayList<String> listOfPattern=new ArrayList<String>();
String ptVisa = "^4[0-9]{6,}$";
listOfPattern.add(ptVisa);
String ptMasterCard = "^5[1-5][0-9]{5,}$";
listOfPattern.add(ptMasterCard);
String ptAmeExp = "^3[47][0-9]{5,}$";
listOfPattern.add(ptAmeExp);
String ptDinClb = "^3(?:0[0-5]|[68][0-9])[0-9]{4,}$";
listOfPattern.add(ptDinClb);
String ptDiscover = "^6(?:011|5[0-9]{2})[0-9]{3,}$";
listOfPattern.add(ptDiscover);
String ptJcb = "^(?:2131|1800|35[0-9]{3})[0-9]{3,}$";
listOfPattern.add(ptJcb);
}
然后,
@Override
public void afterTextChanged(Editable s) {
Log.d("DEBUG", "afterTextChanged : "+s);
String ccNum = s.toString();
for(String p:listOfPattern){
if(ccNum.matches(p)){
Log.d("DEBUG", "afterTextChanged : discover");
break;
}
}
}
对于您的上一个问题,以下主题可以帮助您。
Format credit card in edit text in android
修改强>
例如,如果卡号为16位,则在应用逻辑后添加4位数后的空格后,需要在处理实际卡号时删除这些空格。那么只有上述逻辑才有效。
希望这有帮助。
答案 1 :(得分:0)
使用以下课程验证您的卡片。
public class Validator {
public static final byte VISA = 0;
public static final byte MASTERCARD = 1;
public static final byte AMEX = 2;
public static final byte DINERS_CLUB = 3;
public static final byte CARTE_BLANCHE = 4;
public static final byte DISCOVER = 5;
public static final byte ENROUTE = 6;
public static final byte JCB = 7;
public static boolean validate(final String credCardNumber, final byte type) {
String creditCard = credCardNumber.trim();
boolean applyAlgo = false;
switch (type) {
case VISA:
// VISA credit cards has length 13 - 15
// VISA credit cards starts with prefix 4
if (creditCard.length() >= 13 && creditCard.length() <= 16
&& creditCard.startsWith("4")) {
applyAlgo = true;
}
break;
case MASTERCARD:
// MASTERCARD has length 16
// MASTER card starts with 51, 52, 53, 54 or 55
if (creditCard.length() == 16) {
int prefix = Integer.parseInt(creditCard.substring(0, 2));
if (prefix >= 51 && prefix <= 55) {
applyAlgo = true;
}
}
break;
case AMEX:
// AMEX has length 15
// AMEX has prefix 34 or 37
if (creditCard.length() == 15
&& (creditCard.startsWith("34") || creditCard
.startsWith("37"))) {
applyAlgo = true;
}
break;
case DINERS_CLUB:
case CARTE_BLANCHE:
// DINERSCLUB or CARTEBLANCHE has length 14
// DINERSCLUB or CARTEBLANCHE has prefix 300, 301, 302, 303, 304,
// 305 36 or 38
if (creditCard.length() == 14) {
int prefix = Integer.parseInt(creditCard.substring(0, 3));
if ((prefix >= 300 && prefix <= 305)
|| creditCard.startsWith("36")
|| creditCard.startsWith("38")) {
applyAlgo = true;
}
}
break;
case DISCOVER:
// DISCOVER card has length of 16
// DISCOVER card starts with 6011
if (creditCard.length() == 16 && creditCard.startsWith("6011")) {
applyAlgo = true;
}
break;
case ENROUTE:
// ENROUTE card has length of 16
// ENROUTE card starts with 2014 or 2149
if (creditCard.length() == 16
&& (creditCard.startsWith("2014") || creditCard
.startsWith("2149"))) {
applyAlgo = true;
}
break;
case JCB:
// JCB card has length of 16 or 15
// JCB card with length 16 starts with 3
// JCB card with length 15 starts with 2131 or 1800
if ((creditCard.length() == 16 && creditCard.startsWith("3"))
|| (creditCard.length() == 15 && (creditCard
.startsWith("2131") || creditCard
.startsWith("1800")))) {
applyAlgo = true;
}
break;
default:
throw new IllegalArgumentException();
}
if (applyAlgo) {
return validate(creditCard);
}
return false;
}
public static boolean validate(String creditCard) {
// 4 9 9 2 7 3 9 8 7 1 6
// 6
// 1 x 2 = 2 = (0 + 2) = 2
// 7
// 8 x 2 = 16 = (1 + 6) = 7
// 9
// 3 x 2 = 6 = (0 + 6) = 6
// 7
// 2 x 2 = 4 = (0 + 4) = 4
// 9
// 9 X 2 = 18 = (1 + 8) = 9
// 4
// 6+2+7+7+9+6+7+4+9+9+4 = 70
// return 0 == (70 % 10)
int sum = 0;
int length = creditCard.length();
for (int i = 0; i < creditCard.length(); i++) {
if (0 == (i % 2)) {
sum += creditCard.charAt(length - i - 1) - '0';
} else {
sum += sumDigits((creditCard.charAt(length - i - 1) - '0') * 2);
}
}
return 0 == (sum % 10);
}
private static int sumDigits(int i) {
return (i % 10) + (i / 10);
}
public final static boolean isValidEmail(CharSequence target) {
return !TextUtils.isEmpty(target) && android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}
}