我在PostgreSQL数据库上有两个表,合同和付款。一份合同已完成多笔付款。
我有以下两种模式:
module.exports = function(sequelize, DataTypes) {
var contracts = sequelize.define('contracts', {
id: {
type: DataTypes.INTEGER,
autoIncrement: true
}
}, {
createdAt: false,
updatedAt: false,
classMethods: {
associate: function(models) {
contracts.hasMany(models.payments, {
foreignKey: 'contract_id'
});
}
}
});
return contracts;
};
module.exports = function(sequelize, DataTypes) {
var payments = sequelize.define('payments', {
id: {
type: DataTypes.INTEGER,
autoIncrement: true
},
contract_id: {
type: DataTypes.INTEGER,
},
payment_amount: DataTypes.INTEGER,
}, {
classMethods: {
associate: function(models) {
payments.belongsTo(models.contracts, {
foreignKey: 'contract_id'
});
}
}
});
return payments;
};
我想总结为每份合约支付的所有款项,并使用此功能:
models.contracts.findAll({
attributes: [
'id'
],
include: [
{
model: models.payments,
attributes: [[models.sequelize.fn('sum', models.sequelize.col('payments.payment_amount')), 'total_cost']]
}
],
group: ['contracts.id']
})
但它会生成以下查询:
SELECT "contracts"."id", "payments"."id" AS "payments.id", sum("payments"."payment_amount") AS "payments.total_cost"
FROM "contracts" AS "contracts"
LEFT OUTER JOIN "payments" AS "payments" ON "contracts"."id" = "payments"."contract_id" GROUP BY "contracts"."id";
我没有要求选择payments.id,因为我必须按功能将其包含在我的聚合或组中,如我所犯的错误所述:
可能未处理的SequelizeDatabaseError:错误:列" payments.id" 必须出现在GROUP BY子句中或用于聚合函数
我在这里遗漏了什么吗?我跟随this answer,但即使在那里,我也不了解SQL请求的有效性。
答案 0 :(得分:19)
此问题已在Sequelize 3.0.1上修复,必须排除所包含模型的主键
yourJsonObject.forEach(function(obj) {
console.log(obj.feature_image.ID); // shows 28
});
并且必须在主模型上完成聚合(this github issue中的信息)。
因此,对于我的用例,代码如下
attributes: []
答案 1 :(得分:2)
尝试
group: ['contracts.id', 'payments.id']
答案 2 :(得分:1)
您可能希望从payments
中选择并加入contracts
而不是相反的问题?
答案 3 :(得分:1)
你能把你的功能写成
吗?models.contracts.findAll({
attributes: [
'models.contracts.id'
],
include: [
{
model: models.payments,
attributes: [[models.sequelize.fn('sum', models.sequelize.col('payments.payment_amount')), 'total_cost']]
}
],
group: ['contracts.id']
})