如何将外键数据从一个对象复制到另一个对象?
e.g。
#models.py
class ModelA(models.Model)
field1 = models.CharField(max_length=10)
class ModelB(models.Model)
field2 = models.CharField(max_length=10)
field3 = models.ForeignKey(ModelA)
#views.py
a = ModelA(field1 = 'hello')
b = ModelB(field2 = 'goodbye', field3 = a)
c = ModelB(field2 = 'goodbye again', field3 = a)
d = ModelA(field1 = 'another')
我现在想要给出与之相同的外键数据。即记录b和c。
由于 约翰
答案 0 :(得分:1)
好吧,如果我明白你想要什么。 您必须将模型修改为:
#models.py
class ModelA(models.Model)
field1 = models.CharField(max_length=10)
field2 = models.ForeignKey(ModelA)
class ModelB(models.Model)
field3 = models.CharField(max_length=10)
所以,你可以这样做:
#views.py
b = ModelB(field3 = 'goodbye')
c = ModelB(field3 = 'goodbye again')
a = ModelA(field1 = 'hello', field2 = [b, c])
d = ModelA(field1 = 'another', field2 = a.field2)
或者,如果您希望保留模型,则可以执行以下操作:
#models.py
class ModelA(models.Model)
field1 = models.CharField(max_length=10)
class ModelB(models.Model)
field2 = models.CharField(max_length=10)
field3 = models.ForeignKey(ModelA)
#views.py
a = ModelA(field1 = 'hello')
b = ModelB(field2 = 'goodbye', field3 = a)
c = ModelB(field2 = 'goodbye again', field3 = a)
d = ModelA(field1 = 'another')
#here you get all the objects related to "a"
query = ModelB.objects.filter(field3=a)
#iterated over them
for obj in query:
obj.field3 = d
另一种我认为可能是你想要的方式是:
#models.py
class ModelA(models.Model)
field1 = models.CharField(max_length=10)
field2 = models.ForeignKey(ModelA)
class ModelB(models.Model)
field3 = models.CharField(max_length=10)
field4 = models.ForeignKey(ModelA)
#views.py
a = ModelA(field1 = 'hello')
b = ModelB(field3 = 'goodbye', field4 = a)
c = ModelB(field3 = 'goodbye again', field4 = a)
d = ModelA(field1 = 'another', field2 = a)
我认为已经完成了。但我不知道,我希望它对你有用。 ^^
答案 1 :(得分:0)
我不清楚你究竟在问什么。我假设它不仅仅是
foo.fk_field = bar.fk_field