我在使用这些代码的矩阵时遇到了一些问题,当我手工完成并使用计算工具时,我得到的东西与我的代码给出的东西完全不同。
代码:
public class mult1 {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
double[][] colaO = {{.9,0.05,0.05},{0.05,.9,0.05},{0.05,0.05,.9}};//orginal
double[][] colaD = {{.9,0.05,0.05},{0.05,.9,0.05},{0.05,0.05,.9}};//copy
double[][] colaC = {{.9,0.05,0.05},{0.05,.9,0.05},{0.05,0.05,.9}};//for algs
mult1 test = new mult1();
test.output(colaC);
test.Alg1(colaO, colaD, colaC);
test.output(colaC);
}
public void Alg1(double colaO[][],double colaD[][],double colaC[][]){
for(int i=0;i<colaO.length;i++){
for(int j=0;j<colaO.length;j++){
for(int k=0;k<colaO.length;k++){
colaC[i][j]+=colaO[i][k]*colaD[k][j];
}
}
}
}
public void output(double colaC[][]){
for(int i=0;i<colaC.length;i++){
for(int j=0;j<colaC.length;j++){
System.out.printf("%.3f",colaC[i][j]);
System.out.print(" ");
}
System.out.println();
}
}
}
结果:
---original-----
0.900 0.050 0.050
0.050 0.900 0.050
0.050 0.050 0.900
---what i'm getting------
1.715 0.143 0.143
0.143 1.715 0.143
0.143 0.143 1.715
---should be-----
0.815 0.092 0.092
0.092 0.815 0.092
0.092 0.092 0.815
我不太清楚我在搞乱这个等式的地方
答案 0 :(得分:1)
我要做的第一件事是0-initialise colaC
,因为你在其条目上使用+=
。你现在这样做的方式无法获得正确的结果。
答案 1 :(得分:0)
double[][] colaC = {{.9,0.05,0.05},{0.05,.9,0.05},{0.05,0.05,.9}};//for algs
应该是
double[][] colaC = {{0,0,0},{0,0,0},{0,0,0}};//for algs