如何在scalaz中导入身份操作？

Question

syntax.IdOps似乎没有“伴侣”对象来导入其含义（请参阅selfless pattern），因此很难在REPL中使用它，例如：

scala> val selfish = new scalaz.syntax.ToIdOps{} //I don't want to do this, it feels wrong
selfish: scalaz.syntax.ToIdOps = $anon$1@1adfe356

scala> import selfish._
import selfish._

有没有办法导入它？

Answer 1

https://github.com/scalaz/scalaz/blob/v7.1.2/core/src/main/scala/scalaz/syntax/Syntax.scala#L117

您可以使用scalaz.syntax.id代替new scalaz.syntax.ToIdOps{}

import scalaz.syntax.id._