我有一个包含以下格式的表格(我无法更改)
ClientID | RefAd1 | Cluster Start Date | Cluster End Date
100001 | R1234 | 2014-11-01 |
100001 | R1234 | 2014-11-10 |
100001 | R1234 | 2014-11-20 |
我想提出的是:
ClientID | RefAd1 | Cluster Start Date | Cluster End Date
100001 | R1234 | 2014-11-01 | 2014-11-10
100001 | R1234 | 2014-11-10 | 2014-11-20
100001 | R1234 | 2014-11-20 | NULL
我在这里搜索过,并且自己做了很多尝试,但却无法让它发挥作用。
我无法更新源表(或将另一个表添加到数据库中)所以我将在视图中执行此操作(我可以保存)
任何帮助都会非常感激,并且已经围绕这一天进行了一天,现在有点了!
答案 0 :(得分:1)
使用自我加入获取下一条记录
;WITH CTE AS
(
SELECT ROW_NUMBER() OVER(ORDER BY [Cluster Start Date])RNO,*
FROM YOURTABLE
)
SELECT C1.ClientID,C1.RefAd1,C1.[Cluster Start Date],C2.[Cluster Start Date] [Cluster End Date]
FROM CTE C1
LEFT JOIN CTE C2 ON C1.RNO=C2.RNO-1
编辑:
要更新表格,您可以使用以下查询
;WITH CTE AS
(
SELECT ROW_NUMBER() OVER(ORDER BY [Cluster Start Date])RNO,*
FROM #TEMP
)
UPDATE #TEMP SET [Cluster End Date] = TAB.[Cluster End Date]
FROM
(
SELECT C1.ClientID,C1.RefAd1,C1.[Cluster Start Date],C2.[Cluster Start Date] [Cluster End Date]
FROM CTE C1
LEFT JOIN CTE C2 ON C1.RNO=C2.RNO-1
)TAB
WHERE TAB.[Cluster Start Date]=#TEMP.[Cluster Start Date]
编辑2:
如果您希望ClientId
和RefAd1
完成此操作。
;WITH CTE AS
(
-- Get current date and next date for each type of ClientId and RefAd1
SELECT ROW_NUMBER() OVER(PARTITION BY ClientID,RefAd1 ORDER BY [Cluster Start Date])RNO,*
FROM #TEMP
)
UPDATE #TEMP SET [Cluster End Date] = TAB.[Cluster End Date]
FROM
(
SELECT C1.ClientID,C1.RefAd1,C1.[Cluster Start Date],C2.[Cluster Start Date] [Cluster End Date]
FROM CTE C1
LEFT JOIN CTE C2 ON C1.RNO=C2.RNO-1 AND C1.ClientID=C2.ClientID AND C1.RefAd1=C2.RefAd1
)TAB
WHERE TAB.[Cluster Start Date]=#TEMP.[Cluster Start Date] AND TAB.ClientID=#TEMP.ClientID AND TAB.RefAd1=#TEMP.RefAd1
如果您只想为ClientId
执行此操作,请删除RefAd1
答案 1 :(得分:1)
如果你只想要你描述的视图,这是脚本:
CREATE VIEW v_name as
SELECT
ClientId,
RefAd1,
[Cluster Start Date],
( SELECT
min([Cluster Start Date])
FROM yourTable
WHERE
t.[Cluster Start Date] < [Cluster Start Date]
) as [Cluster End Date]
FROM yourtable t