如何在Alert Dialog的onclick监听器中访问非最终变量而不使其成为最终变量

Question

@Override
    public void onItemClick(AdapterView<?> parent, View view, int position,
            long id) {
        String choice="";
        AlertDialog.Builder builder1 = new AlertDialog.Builder(parent.getContext());
        builder1.setMessage("Do you want to accept this vendor's quote?");
        builder1.setCancelable(true);
        builder1.setPositiveButton("Yes",
                new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog, int id) {
             choice= "true" //cant access non final variable
            }
        });
        builder1.setNegativeButton("No",
                new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog, int id) {
                dialog.cancel();
            }
        });

        AlertDialog alert11 = builder1.create();
        alert11.show();
if(choice.equals("true"){
// do something
}

    }

如何在不使其成为最终版本的情况下访问“选择”变量，或者有任何其他方式来了解用户是否按下了正按钮或负按钮

Answer 1

将您的变量声明为类中的字段：

public class YourClass {
    private String choice;
    ...
}

Answer 2

干净的方法是让onClick方法调用＆＃34; setter＆＃34;你父类的方法。

public class Activity {
  private boolean choice = false;

...

  //In your method
  builder1.setPositiveButton("Yes",
            new DialogInterface.OnClickListener() {
              public void onClick(DialogInterface dialog, int id) {
                setChoice(true);
              }
            });

  }

...

  public void setChoice(boolean choice) {
    this.choice = choice;
  }
}

Answer 3

变量必须是最终的，例如Eclipse说：

  

不能引用在不同方法中定义的内部类中的非最终变量选择

Answer 4

将变量声明到外部，就在类定义中。