在Android中使用notifyItemRemoved或notifyDataSetChanged与RecyclerView

时间:2015-01-28 10:02:54

标签: android android-listview android-recyclerview notifydatasetchanged

我正在创建一个使用RecyclerView显示的卡片列表,其中每张卡片都有一个按钮,可以从列表中删除该卡片。

当我使用 notifyItemRemoved()删除RecyclerView中的卡时,它会删除项目并设置动画,但列表中的数据未正确更新。

如果不是这样,我会切换到 notifyDataSetChanged(),然后列表中的项目会被删除并正确更新,但这些卡片不会动画。

有人有使用notifyItemRemoved()的经验并知道它的行为与notifyDataSetChanged不同吗?

以下是我正在使用的一些代码:

private List<DetectedIssue> issues = new ArrayList<DetectedIssue>();

@Override
public void onBindViewHolder(RecyclerView.ViewHolder holder, int position) {
    // - get element from your dataset at this position
    // - replace the contents of the view with that element
    if(position >0){
        RiskViewHolder riskHolder = (RiskViewHolder)holder;
        final int index = position - 1;
        final DetectedIssue anIssue = issues.get(index);

        riskHolder.button.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                try {
                    int index = issues.indexOf(anIssue);
                    issues.remove(anIssue);
                    notifyItemRemoved(index);

                    //notifyDataSetChanged();
                } catch (SQLException e) {
                    e.printStackTrace();
                }
            }
        });
    }
}

@Override
public int getItemCount() {
    return (issues.size()+1);
}

8 个答案:

答案 0 :(得分:79)

在notifyItemRemoved(position)之后使用 notifyItemRangeChanged(position,getItemCount()); ;
你不需要使用索引,只需使用位置。请参阅下面的代码。

private List<DetectedIssue> issues = new ArrayList<DetectedIssue>();

@Override
public void onBindViewHolder(RecyclerView.ViewHolder holder, int position) {
    // - get element from your dataset at this position
    // - replace the contents of the view with that element
    if(position >0){
        RiskViewHolder riskHolder = (RiskViewHolder)holder;

        riskHolder.button.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                try {
                    issues.remove(position);
                    notifyItemRemoved(position);
                    //this line below gives you the animation and also updates the
                    //list items after the deleted item
                    notifyItemRangeChanged(position, getItemCount());

                } catch (SQLException e) {
                    e.printStackTrace();
                }
            }
        });
    }
}

@Override
public int getItemCount() {
    return issues.size();
}

答案 1 :(得分:17)

尝试

public void removeItem(int position) {
    this.taskLists.remove(position);
    notifyItemRemoved(position);
    notifyItemRangeChanged(position, getItemCount() - position);
}

并且像魅力一样工作。

答案 2 :(得分:9)

我的错误, notifyItemChanged(位置)无奈,位置项可以删除,位置+ 1的项目很好,但是项目从位置+ 2开始,你会得到一个异常,请使用<强> notifyItemRangeChanged(位置,getItemCount());  在 notifyItemRemoved(position);

之后 像这样:

public void removeData(int position) {
    yourdatalist.remove(position);
    notifyItemRemoved(position);
    notifyItemRangeChanged(position,getItemCount());
}

答案 3 :(得分:0)

正如@pskink建议我的notifyItemRemoved(index+1)应该是(index + 1),可能是因为我保留了顶部索引,即position=0作为标题。

答案 4 :(得分:0)

您可以使用getLayoutPosition()

中的RecyclerView.ViewHolder

getLayoutPosition()提供了布局中项目的确切位置,代码为

holder.removeButton.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                //Position for remove
                int modPosition= holder.getLayoutPosition();
                //remove item from dataset
                numbers.remove(modPosition);
                //remove item from recycler view
                notifyItemRemoved(modPosition);
            }
        });

答案 5 :(得分:0)

**my solution looks like this**

this way is unnecessary to use the heavy method:
 //notifyItemRangeChanged(xx,xx)

/**
 * 
 * recyclerView的item中的某一个view,获取其最外层的viewParent,也就是item对应的layout在adapter中的position
 *
 * @param recyclerView
 * @param view:can be the deep one inside the item,or the item itself .
 * @return
 */
public static int getParentAdapterPosition(RecyclerView recyclerView, View view, int parentId) {
    if (view.getId() == parentId)
        return recyclerView.getChildAdapterPosition(view);
    View viewGroup = (View) view.getParent();
    if (viewGroup != null && viewGroup.getId() == parentId) {
        return recyclerView.getChildAdapterPosition(viewGroup);
    }
    //recursion
    return getParentAdapterPosition(recyclerView, viewGroup, parentId);
}




//wherever you set the clickListener .
holder.setOnClickListener(R.id.rLayout_device_item, deviceItemClickListener);
holder.setOnLongClickListener(R.id.rLayout_device_item, deviceItemLongClickListener);


@Override
public boolean onLongClick(View v) {
    final int position = ViewUtils.getParentAdapterPosition(rVDevicesList, v, R.id.rLayout_device_item);
    return true;
}

答案 6 :(得分:0)

在我的情况下,我使用Content Provider和带有Cursor的Custom RecyclerView Adapter。这行代码是您通知的地方:

getContext().getContentResolver().notifyChange(uri, null);

假设在您的recyclerView适配器(删除按钮)中:

Uri currentUri = ContentUris.withAppendedId(DatabaseContract.ToDoEntry.CONTENT_URI_TODO, id);
int rowsDeleted = mContext.getContentResolver().delete(currentUri, null, null);
if (rowsDeleted == 0) {
    Log.d(TAG, "onClick: Delete failed");
} else {
    Log.d(TAG, "onClick: Delete Successful");
}

在您的数据库提供商中:

case TODO_ID:
selection = DatabaseContract.ToDoEntry._ID + "=?";
selectionArgs = new String[] {String.valueOf(ContentUris.parseId(uri))};
rowsDeleted = database.delete(DatabaseContract.ToDoEntry.TODO_TABLE_NAME, selection, selectionArgs);
if (rowsDeleted != 0){
    getContext().getContentResolver().notifyChange(uri, null);
}
return rowsDeleted;

答案 7 :(得分:-2)

您应该在ViewHolder类中添加删除侦听器

 button.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                   onCancel(getAdapterPosition());

            }
        });

  private void onCancel(int position) {
        if (position >= issues.size())
            return;
        issues.remove(position);
        notifyItemRemoved(position);
    }