C循环开关?

时间:2015-01-28 09:23:58

标签: c loops switch-statement

所以这是我的代码:

我的问题是我想用一个while循环来循环switch语句,具体取决于char响应得到的结果(在底部)。

我已经尝试将整个switch语句放入do while循环(失败)。

无论如何我是这种语言的新手,我想尝试制作一个复杂的程序。

#include <stdio.h>
#include <stdlib.h>
#define LINE  "____________________"
#define TITLE "Tempature Converter"
#define NAME  "Jose Meza II"

char scale, response;
float temp, celTemp, farTemp, kelTemp;

int main() {

printf("\n \t %s \n \t %s \n", LINE, TITLE );
printf("\t by %s \n \t %s \n\n", NAME, LINE );

printf("Enter C for Celsius, F for Fahrenheit, or K for Kelvin: ");
scanf("%c", &scale);
printf("Tempature value: ");
scanf("%f", &temp);

switch (scale)
{
    case ('c'): /* convert to Fahrenheit and Kelvin */
    {
        farTemp = (temp * 9 / 5) + 32;
        kelTemp = temp + 273.15;
        printf("Fahrenheit = %.2f\n", farTemp);
        printf("Kelvin = %.2f\n\n", kelTemp);
        break;
    } /* end case 'c' */
    case ('f'): /* convert to Celsius and Kelvin */
    {
        celTemp = (temp - 32) * 5 / 9;
        kelTemp = (temp - 32) * 5 / 9 + 273.15;
        printf ("Celsius = %.2f\n", celTemp);
        printf ("Kelvin = %.2f\n\n", kelTemp);
        break;
    } /* end case 'f' */
    case ('k'): /* convert to Celsius and Fahrenheit */
    {
        celTemp = temp - 273.15;
        farTemp = (temp - 273.15) * 9 /5 + 32;
        printf("Celsius = %.2f\n", celTemp);
        printf("Fahrenheit = %.2f\n\n", farTemp);
        break;
    } /* end case 'k' */
    default: exit(0); /* no valid temperature scale was given, exit program */
} /* end switch */

printf("Enter in C to Continue, or S to stop: ");
scanf(" %c", &response);

return 0;
}

我该怎么办?

我试过了:

do
{
    printf("Enter C for Celsius, F for Fahrenheit, or K for Kelvin: ");
    scanf("%c", &scale);
    printf("Tempature value: ");
    scanf("%f", &temp);

    switch (scale)
    {
        case ('c'): /* convert to Fahrenheit and Kelvin */
        {
            farTemp = (temp * 9 / 5) + 32;
            kelTemp = temp + 273.15;
            printf("Fahrenheit = %.2f\n", farTemp);
            printf("Kelvin = %.2f\n\n", kelTemp);
            break;
        } /* end case 'c' */
        case ('f'): /* convert to Celsius and Kelvin */
        {
            celTemp = (temp - 32) * 5 / 9;
            kelTemp = (temp - 32) * 5 / 9 + 273.15;
            printf ("Celsius = %.2f\n", celTemp);
            printf ("Kelvin = %.2f\n\n", kelTemp);
            break;
        } /* end case 'f' */
        case ('k'): /* convert to Celsius and Fahrenheit */
        {
            celTemp = temp - 273.15;
            farTemp = (temp - 273.15) * 9 /5 + 32;
            printf("Celsius = %.2f\n", celTemp);
            printf("Fahrenheit = %.2f\n\n", farTemp);
            break;
        } /* end case 'k' */
        default: exit(0); /* no valid temperature scale was given, exit     program */
    } /* end switch */

    printf("Enter in C to Continue, or S to stop: ");
    scanf(" %c", &response);
}
while(response == 'c');

1 个答案:

答案 0 :(得分:2)

最常见的方法是使用do-while循环。进行以下更改

<德尔> 1.将`response`初始化为`C`。 2.在`do..while()`循环中放置`switch` case和next`printf()`和`scanf()`。 3.在`while()`条件下,检查`while(c ==`C`)`。

编辑后,问题似乎是

scanf("%c", &scale);

你需要在%c之前有一个空格,比如

scanf(" %c", &scale);

最后在\n之后避免 ENTER [C]。