在php中创建mysqli
对象时,可以将其提供给数据,以便它可以连接。一个例子:
$mysqli = new mysqli($address, $user, $pass, $database);
是否可以从结果对象中获取您提供的数据?
答案 0 :(得分:1)
否强>
在用于开始连接之后,数据根本不存在。这是print_r
:
mysqli Object
(
[affected_rows] => 0
[client_info] => mysqlnd 5.0.11-dev - 20120503 - $Id: [not sure if this was sensitive information, so redacted. was just a long string of numbers] $
[client_version] => 50011
[connect_errno] => 0
[connect_error] =>
[errno] => 0
[error] =>
[error_list] => Array
(
)
[field_count] => 0
[host_info] => localhost via TCP/IP
[info] =>
[insert_id] => 0
[server_info] => 5.5.36
[server_version] => 50536
[stat] => Uptime: 294546 Threads: 1 Questions: 351 Slow queries: 0 Opens: 53 Flush tables: 1 Open tables: 0 Queries per second avg: 0.001
[sqlstate] => 00000
[protocol_version] => 10
[thread_id] => 99
[warning_count] => 0
)