Question

我在当前项目中使用了两张UIAction表。我可以让一个人工作得很好但是当我插入第二个动作表时，它会运行与第一个相同的争论。我如何单独定义动作表？

-(IBAction) phoneButtonClicked:(id)sender
{
    // open a dialog with just an OK button
    UIActionSheet *actionSheet = [[UIActionSheet alloc] initWithTitle:nil
                                                        delegate:self cancelButtonTitle:@"Cancel" 
                                                        destructiveButtonTitle:nil 
                                                        otherButtonTitles:[NSString stringWithFormat:@"Phone: %@",phone],nil];
    actionSheet.actionSheetStyle = UIActionSheetStyleDefault;
    [actionSheet showInView:self.view]; // show from our table view (pops up in the middle of the table)
    [actionSheet release];  
}

-(IBAction) mapButtonClicked:(id)sender
{
    // open a dialog with just an OK button
    UIActionSheet *mapActionSheet = [[UIActionSheet alloc] initWithTitle:nil
                                                        delegate:self cancelButtonTitle:@"Cancel" 
                                                        destructiveButtonTitle:nil 
                                                        otherButtonTitles:[NSString stringWithFormat:@"Map"],nil];
    mapActionSheet.actionSheetStyle = UIActionSheetStyleDefault;
    [mapActionSheet showInView:self.view];  // show from our table view (pops up in the middle of the table)
    [mapActionSheet release];   
}


-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex {
        if(buttonIndex == 0){
            NSString *callPhone = [NSString stringWithFormat:@"tel:%@",phone];
            NSLog(@"Calling: %@", callPhone);
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:callPhone]];
    }
}

Answer 1

UIActionSheet是UIView的子视图，因此您可以使用tag属性。

Answer 2

制作actionSheets实例变量并在委托方法中测试返回的操作表。

或者，编写自己的UIActionSheet（和UIAlert的子类，它会遭受同样的烦恼），在捕获返回时将回调发送给委托对象。

从UIActionSheets帮助创建动作

2 个答案: