如何计算＆amp;同一查询中同一个表的其他列？

Question

我正在尝试下面的MySql查询 -

SELECT count(*), bug_id, 
       bug_status, 
       resolution, 
       short_desc, 
       DATE_FORMAT(deadline, "%m/%d/%Y")AS deadline
FROM   bugs 
WHERE  ( bug_status IN ( 'RESOLVED', 'VERIFIED', 'INTEST' ) 
         AND deadline BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 30 DAY) 
       ) 
        OR ( bug_status IN ( 'RESOLVED', 'VERIFIED', 'INTEST' ) 
             AND deadline BETWEEN DATE_SUB(CURDATE(), INTERVAL 30 DAY) AND 
                                  CURDATE() )        
       ORDER BY deadline ASC

但它返回的结果只有一列而不是所有96个条目..

什么是更好的主意，以便我先得到计数然后得到所有结果？

Answer 1

COUNT()子句中存在SELECT（或任何其他聚合函数）会将查询转换为聚合查询。如果没有GROUP BY子句，聚合查询必须只返回一行。

如果必须在每一行中返回count项，则必须在连接的单行子查询中获取它。像这样的东西可以解决问题。

SELECT b.cnt, a.*
  FROM table a
  JOIN (SELECT COUNT(*) cnt FROM table) b ON 1=1

但是对于你有的大问题，你必须在我提到table的地方重复两次。

Answer 2

如果你想在每一行中完整计数，那么在MySQL中有点难看。你基本上有两个选择：

1. 执行两个单独的查询并将结果放回调用代码
中
2. 在MySQL中有效地执行两个单独的查询，并将结果放在MySQL中

以下是如何将它们放在MySQL中 - 注意你的WHERE逻辑必须如何重复：

SELECT
  CountOnly.RowCount,
  bug_status,
  resolution,
  short_desc,
  DATE_FORMAT(deadline, '%m/%d/%Y') AS deadline
FROM bugs
INNER JOIN (
  SELECT COUNT(*) AS RowCount
  FROM bugs
  WHERE 
   ( bug_status IN ( 'RESOLVED', 'VERIFIED', 'INTEST' ) 
     AND deadline BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 30 DAY) 
   ) 
   OR ( bug_status IN ( 'RESOLVED', 'VERIFIED', 'INTEST' ) 
        AND deadline BETWEEN DATE_SUB(CURDATE(), INTERVAL 30 DAY) AND CURDATE() )
) CountOnly ON 1 = 1
WHERE
 ( bug_status IN ( 'RESOLVED', 'VERIFIED', 'INTEST' ) 
   AND deadline BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 30 DAY) 
 ) 
 OR ( bug_status IN ( 'RESOLVED', 'VERIFIED', 'INTEST' ) 
      AND deadline BETWEEN DATE_SUB(CURDATE(), INTERVAL 30 DAY) AND CURDATE() )