如何用mongoose聚合推送特定字段的值

Question

我在路线中使用此代码：

    MyModel.aggregate(
        [
            { "$group": { 
                    "_id": "$date",
                    "participants": { "$sum": "$participants" },
                    "peoples": { $sum: 1 }
                } 
            },
        ],
         function(err, result) {
           console.log(result)
         }
  ......etc......

这是聚合日期，参与者和人民，但我想访问名称字段，我尝试这样：

"_id": "$date",
"name": "$name",
"participants": { "$sum": "$participants" },
"peoples": { $sum: 1 }

但正在回归：

{ [MongoError: exception: the group aggregate field 'name' must be defined as an expression inside an object]
  name: 'MongoError',
  errmsg: 'exception: the group aggregate field \'some\' must be defined as an expression inside an object',
  code: 15951,
  ok: 0 }

我做错了什么？

Answer 1

您需要$first运算符。即：

MyModel.aggreagate(
    [
        { "$group": {
            "_id": "$date",
            "name": { "$first": "$name" },
            "participants": { "$sum": "$participants" }, 
            "peoples": { "$sum": 1 }
        },
    ],
    function(err,results) { 
        // rest of processing.
    }
);

怀疑你的＆＃34;人民＆＃34;和＆＃34;参与者＆＃34;字段也是错误的。但这是另一个在这里脱离背景的问题。