Question

我之前在SO上有很好的帮助来分析停车数据。这是我的问题：

select parking_meter_id, avg(cnt) from
  (select parking_meter_id, count(*) as cnt, to_char(start,'YYYYMMDD') as day
  from parking_transactions
  where start >= now() - interval '3 month' -- last three months
  and to_char(start,'YYYYMMDD') < to_char(now(),'YYYYMMDD') -- but not today
  and to_char(start,'D') = to_char(now(),'D') -- same weekday
  and to_char(now(),'HH24MISS') between to_char(start,'HH24MISS') and to_char(stop,'HH24MISS') -- same time
  group by parking_meter_id, to_char(start,'YYYYMMDD') -- group by day
) as parking_transactions group by parking_meter_id

它确实有效并显示活动交易的平均数，这是因为今天（now（））的交易被过滤掉了。

在同一次运行中，是否有可能让查询也返回当前活动的事务：

select count(*) as cnt from parking_transactions where now() between start and stop

这样可以轻松地将当前状态与历史状态进行比较吗？

我的表结构是：

parking_meter_id, start, stop

目前我得到以下输出：

parking_meter_id, avg(cnt) minus today

我想得到以下输出：

parking_meter_id, avg(cnt) minus today, count(*) for today only

- 但今天不是忽略今天交易的where子句。

截至目前的输出示例如下：

 parking_meter_id | cnt |   day    
------------------+-----+----------
             4406 |   1 | 20141217
             4406 |   5 | 20150107
             4406 |   1 | 20150121
             4406 |   3 | 20150128
             4406 |   3 | 20150114

我想回复：

 parking_meter_id | avg(cnt-without-today) |   cnt-day    
------------------+-----+------------------------------
             4406 |   2.6                  | 3

Answer 1

使用WITH为daily count和avg count minus today创建临时表并加入表格以获得所需的结果

SQL Fiddle

<强> SQL

WITH daily_count AS  -- temp table to store daily counts 
(
         SELECT   parking_meter_id,
                  COUNT(*)                  AS cnt,
                  to_char(start,'YYYYMMDD') AS day
         FROM     parking_transactions
         WHERE    start >= now() - interval '3 month' -- last three months
         AND      to_char(start,'D') = to_char(now(),'D') -- same weekday
         AND      to_char(now(),'HH24MISS') BETWEEN to_char(start,'HH24MISS') AND to_char(stop,'HH24MISS') -- same time
         GROUP BY parking_meter_id,
                  to_char(start,'YYYYMMDD') -- group by parking meter id and day
), avg_count_minus_today AS -- temp table to store avg count minus today 
(
         SELECT   parking_meter_id,
                  AVG(cnt) AS avg_count
         FROM     daily_count
         WHERE    day < to_char(now(),'YYYYMMDD') -- but not today
         GROUP BY parking_meter_id 
)
SELECT     a.parking_meter_id,
           a.avg_count, --avg count minus today
           d.cnt AS today_count
FROM       avg_count_minus_today a
INNER JOIN daily_count d
ON         a.parking_meter_id= d.parking_meter_id AND d.day=to_char(now(),'YYYYMMDD'); --today in daily count

获取停车数据的历史计数和当前计数

1 个答案: