我的C ++中有一个像这样的结构
struct ST_HDTextInfo
{
char* font_name;
char* text;
unsigned int font_color;
unsigned int background_color;
int style;
int font_size;
struct ST_HDTextInfo* next;
};
我在我的C#代码中重新声明它
[StructLayout(LayoutKind.Sequential,Pack=4)]
unsafe struct ST_HDTextInfo
{
[MarshalAsAttribute(UnmanagedType.ByValTStr, SizeConst = 25)]
public fixed char font_name[25];
[MarshalAs(UnmanagedType.ByValTStr, ArraySubType = UnmanagedType.I1, SizeConst = 20)]
public char[] text;
[MarshalAs(UnmanagedType.SysUInt)]
public uint font_color;
[MarshalAs(UnmanagedType.SysUInt)]
public uint background_color;
[MarshalAs(UnmanagedType.SysInt)]
public EN_FontStyle style;
[MarshalAs(UnmanagedType.SysInt)]
public int font_size;
[MarshalAs(UnmanagedType.SysInt)]
public ST_HDTextInfo* next;
};
字段 next 是指向相同结构的指针。当我使用 char [] var 作为字符串变量时,因为结构没有修复大小VS在公共ST_HDTextInfo * 下一步 时出错 但是当使用fixed char var [SIZE_OF_VAR]时问题解决但又出现了另一个错误。填充char *变量是一个新问题!我使用此代码将counrt字符串转换为char *
IntPtr p = Marshal.StringToHGlobalAuto("Poor Richard");
char* newCharStr = (char*)(p.ToPointer());
text_info.font_name = newCharStr;
在这个站中我的字符串转换为char *但是VS接受此错误"作业的左侧必须是变量,属性或索引器" !!!
答案 0 :(得分:0)
我解决了这个问题。我使用这个示例代码
[StructLayoutAttribute(LayoutKind.Explicit, CharSet = CharSet.Auto, Size=80)]
internal unsafe struct ST_HDTextInfo
{
[FieldOffset(0)]
public fixed char text[25];
[FieldOffset(0)]
public fixed char font_name[20];
[MarshalAs(UnmanagedType.I4)]
[FieldOffset(0)]
public uint font_color;
[MarshalAs(UnmanagedType.I4)]
[FieldOffset(0)]
public uint background_color;
[MarshalAs(UnmanagedType.I4)]
[FieldOffset(0)]
public EN_FontStyle style;
[MarshalAs(UnmanagedType.I4)]
[FieldOffset(0)]
public int font_size;
[FieldOffset(80 - sizeof(long))]
public ST_HDTextInfo* next;
};