Question

这是基本的多选框：

<select name="State" size="5" multiple="multiple">

    <option value="1">Kedah</option>
    <option value="2">Kelantan</option>

</select>

问题是，如何从数据库中获取选项值，而不是手动输入选项值。

我的数据库看起来像这样：

    mysql> select sta_id,sta_name
    -> from sys_state
    -> where sta_status = '1';

+--------+----------------------------------+
| sta_id | sta_name                         |
+--------+----------------------------------+
|     01 | JOHOR                            |
|     02 | KEDAH                            |
|     03 | KELANTAN                         |
|     04 | MELAKA                           |
|     05 | NEGERI SEMBILAN                  |
|     06 | PAHANG                           |
|     07 | PULAU PINANG                     |
|     08 | PERAK                            |
|     09 | PERLIS                           |
|     10 | SELANGOR                         |
|     11 | TERENGGANU                       |
|     12 | SABAH                            |
|     13 | SARAWAK                          |
|     14 | WILAYAH PERSEKUTUAN KUALA LUMPUR |
|     15 | WILAYAH PERSEKUTUAN LABUAN       |
|     16 | WILAYAH PERSEKUTUAN PUTRAJAYA    |
+--------+----------------------------------+

Answer 1

首先，您应该连接到数据库PHP Mysql Connection

下一步是获取这些行并将数据写入变量（它可以是数组或任何对象，在我的例子中它是一个数组）PHP MySQL Data Select：

$sql = "SELECT sta_id,sta_name FROM sys_state WHERE sta_status = '1'";
$result = $conn->query($sql);
$resultData = [];
if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
         $resultData[$row['sta_id']] = $row['sta_name'];
    }
}

最后，在html页面上打印：

<select name="State" size="5" multiple="multiple">
<?php
foreach ($resultData as $key => $value) {
    echo '<option value="'.$key.'">'.$value.'</option>';
}
?>
</select>

Answer 2

尝试

<?php $qry = mysql_query("select sta_id,sta_name from sys_state where sta_status = '1'");?>

<select name="State" size="5" multiple="multiple">
<?php while($row = mysql_fetch_assoc($qry)){?>
    <option value="<?php echo $row['sta_id'];?>"><?php echo $row['sta_name'];?></option>
 <?php }?>
</select>

注意： - mysql_*已被弃用，使用mysqli_*或PDO

Answer 3

尝试 -

$mysqli = new mysqli("localhost", "user", "password", "database");
$res = $mysqli->query("select sta_id,sta_name from sys_state where sta_status = '1'");

?>
<select name="State" size="5" multiple="multiple">
<?php

while ($row = $res->fetch_assoc()) {
    echo "<option value='".$row['sta_id']."'>".$row['sta_name']."</option>";
}
?>
</select>

Answer 4

<?php $qry = mysql_query("select sta_id,sta_name from sys_state where sta_status = '1'");

$dropdown ='<select name="State" size="5" multiple="multiple">';
while($row = mysql_fetch_assoc($qry)){
    $dropdown .='<option value="'.$row['sta_id'].'">'.$row['sta_name'].'</option>';
 }
$dropdown .= '</select>';
echo $dropdown;

这将回显动态值的下拉列表

Answer 5

嗯，基本上你只能echo他们

$dsn = "mysql:host=localhost;dbname=x"; 
$user="root";
$password="";
try{
$connect = new PDO($dsn,$user,$password); // PDO= PHP Data Object
$connect->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION);
}catch(PDOException $e){echo $e->getMessage();}


$select = $connect->query("select sta_id,sta_name from sys_state where sta_status = '1';"); 

echo "<select name=\"State\" size=\"5\" multiple=\"multiple\">";

foreach ($select as $temp){


   echo "<option value=\"1\">".temp["sta_name"]."  </option>";
    ......
    ....


}
echo "</select>";

$connect=null;// CLOSE CONNECTION

但将它们构建成函数会更好

Answer 6

我设法这样做了：

<?php     // MULTI SELECTION 



    $sql1 = " SELECT sta_id,sta_name FROM dof_perkhidmatan.sys_state WHERE sta_status = '1' ";

    $result1 =  $db->sql_query($sql1,END_TRANSACTION);

    if($db->sql_numrows($result1) > 0)
    {

    ?>

     <select id="State" name="State" size="16" multiple="multiple">
     <?php

    // output data of each row
    while($row_select = $db->sql_fetchrow($result1))        
        {
         echo '<option value="'.$row_select['sta_id'].'">'.$row_select['sta_name'].'</option>';
        }


    ?>
    </select>
    <?php
    }
    ?>

Answer 7

试试这个，它对我来说很好用

<?php
<!-- Connect to your database-->

require 'dbconnect.php';

<!--  Fetch required data from the database-->

$sql="SELECT sta_id,sta_name from sys_state WHERE sta_status = '1' ";

$result = mysqli_query($con, $sql);

?>
<select multiple size="6">

<?php while($row = mysqli_fetch_assoc($result)){?>
          <option value="<?php echo $row['sta_id']; ?>"> <?php echo $row['sta_name']; ?></option>

 <?php
}
?>
 </select>

显示多选框内数据库的值

7 个答案: