Question

代码是：

int main()
{
    displayOwe(getOwe(), customerpaid());
    displayChange(dollars, quarters, dimes, nickels, pennies);
    return 0;
}

float getOwe()
{
    float owed;
    printf("\nHow much does the customer owe? ");
    scanf("%f" ,&owed );    
    return owed;
}

float customerpaid()
{
    float paid;
    printf("\nHow much did the customer pay? ");            
    scanf("%f" ,&paid );
    return paid;
}

float calculateTotal (float paid, float owed)
{
    float answer;
    answer = paid - owed;
    return answer;
}

float displayOwe(float owed , float paid)
{   
    printf("\nCustomer owes $%0.2f and paid $%0.2f.", owed, paid);
}

int displayChange(int dollars, int quarters, int dimes, int nickels, int pennies)
{
    dollars= ;
    quarters=
    dimes=
    nickels=
    pennies=
    printf("\n\nCashier should refund %d dollars, %d quarters, %d dimes, %d nickels, and %d pennies.", dollars, quarters, dimes, nickels, pennies); 
}

我必须创建一个C程序来计算变化，该变更显示客户欠多少以及客户付多少钱。我做了那部分，它完美无瑕地工作，但我不知道如何使程序显示出纳员需要返回给客户多少美元，四分之一，硬币，镍币和便士。任何帮助将不胜感激。

Answer 1

displayChange需要两个额外的参数 - 浮动欠款，浮动支付。其他参数应为“＆amp;”因为它们是输出参数。

在displayChange中我会将float转换为int：

int iOwed = owed * 100;  
int iPaid = paid * 100;

现在一分钱是1，而不是0.01，一美元是100，而不是1;

一旦你将它们作为整体，首先要做出改变：

int change = iPaid - iOwed;

然后从最大货币单位到最小货币单位获得每个欠款的数量 - 首先划分，然后得到余数。

dollars =  change / 100;

使用模数运算符得到余数：

remainder  = change % 100;

然后继续使用25,10,5和1来计算剩余值，用于四分之一，硬币，镍币和便士。

quarters = remainder / 25;

remainder = remainder % 25;

如何使我的C程序以美元，四分之一，硬币，镍币和便士的形式返回？

1 个答案: