Question

我一直在寻找一种方法将变量id从index.php转移到（以及其他）update-check.php。最初这导致无休止的加载时间 - 即页面在localhost上永远等待。我将其缩小为session_start();导致此错误。如果我删除session_start();并将'stories/'. $_SESSION['id'] .'.txt';替换为实际的id变量（例如'stories/film.txt';），那么除了我需要使用该变量这一事实外，无需加载任何问题。

我也注意到我有时在控制台中获得Failed to load resource: net::ERR_CACHE_MISS。

我试图修补并发现为什么会发生这种情况以及如何解决它，但我的大脑受伤了，我希望在这种情况下有更多经验的人能够在这个情况下提供一些帮助（这是值得一提的是，我不习惯使用PHP或后端，来自前端设计师。）

编辑 - 所以问题不在于PHP而是这个脚本 是否可以在保持功能的同时调整此脚本以保持良好状态？

/**
 * AJAX long-polling
 *
 * 1. sends a request to the server (without a timestamp parameter)
 * 2. waits for an answer from server.php (which can take forever)
 * 3. if server.php responds (whenever), put data_from_file into #response
 * 4. and call the function again
 *
 * @param timestamp
 */
function getContent(timestamp)
{
    var queryString = {'timestamp' : timestamp};

    $.ajax(
        {
        type: 'GET',
        url: 'update-check.php',
        data: queryString,
        success: function(data){
            // put result data into "obj"
            var obj = jQuery.parseJSON(data);
            // put the data_from_file into #response
            $('#response').html(obj.data_from_file);
            // call the function again, this time with the timestamp we just got from server.php
            getContent(obj.timestamp);
                //timeout to avoid endless loading? didn't make a difference
                timeout: 3000 // sets timeout to 3 seconds

            }
        }
    );
}

// initialize jQuery
$(function() {
    getContent();
});

更新check.php

<?php
session_start();


/**
 * Server-side file.
 * This file is an infinitive loop. Seriously.
 * It gets the file data.txt's last-changed timestamp, checks if this is larger than the timestamp of the
 * AJAX-submitted timestamp (time of last ajax request), and if so, it sends back a JSON with the data from
 * data.txt (and a timestamp). If not, it waits for one seconds and then start the next while step.
 *
 * Note: This returns a JSON, containing the content of data.txt and the timestamp of the last data.txt change.
 * This timestamp is used by the client's JavaScript for the next request, so THIS server-side script here only
 * serves new content after the last file change. Sounds weird, but try it out, you'll get into it really fast!
 */

// set php runtime to unlimited
set_time_limit(0);

/* $data_source_file = 'stories/film.txt'; */
$data_source_file = 'stories/'. $_SESSION['id'] .'.txt';

// main loop
while (true) {

    // if ajax request has send a timestamp, then $last_ajax_call = timestamp, else $last_ajax_call = null
    $last_ajax_call = isset($_GET['timestamp']) ? (int)$_GET['timestamp'] : null;

    // PHP caches file data, like requesting the size of a file, by default. clearstatcache() clears that cache
    clearstatcache();
    // get timestamp of when file has been changed the last time
    $last_change_in_data_file = filemtime($data_source_file);

    // if no timestamp delivered via ajax or data.txt has been changed SINCE last ajax timestamp
    if ($last_ajax_call == null || $last_change_in_data_file > $last_ajax_call) {

        // get content of data.txt
        $data = file_get_contents($data_source_file);

        // put data.txt's content and timestamp of last data.txt change into array
        $result = array(
            'data_from_file' => $data,
            'timestamp' => $last_change_in_data_file
        );

        // encode to JSON, render the result (for AJAX)
        $json = json_encode($result);
        echo $json;

        // leave this loop step
        break;

    } else {
        // wait for 1 sec (not very sexy as this blocks the PHP/Apache process, but that's how it goes)
        sleep( 1 );
        continue;
    }
}

Answer 1

我最终使用setcookie("currentID", $id, time()+3600);而不是通过AJAX传递变量。可能不是推荐的推荐路径，但它适用于我需要它做的事情。

如何防止脚本为PHP造成无限的加载时间？

1 个答案: