我正在使用SQL Server,并且有一个表(Table_Date),其中包含' date'领域。我想在此字段中插入所有2015年日期。
它应该有365个不同的行,2015年的每一天都有1行。
答案 0 :(得分:2)
一种方法是使用递归CTE:
with dates as (
select cast('2015-01-01' as date) as thedate
union all
select dateadd(day, 1, thedate)
from dates
where thedate < '2015-12-31'
)
select *
from dates
option (maxrecursion 0);
另一种方法是使用至少有365行的表。 master..spt_values
通常用于此目的:
select dateadd(day, seqnum - 1, '2015-01-01')
from (select row_number() over (order by ()) as seqnum
from master..spt_values
) t
where seqnum <= 365;
答案 1 :(得分:1)
以这种方式:
CREATE TABLE #nums(num INT);
INSERT INTO #nums VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9);
WITH cteDays AS
(
SELECT 100*d100.num + 10*d10.num + d1.num AS YearDay
FROM #nums AS d1
CROSS JOIN #nums AS d10
CROSS JOIN #nums AS d100
WHERE d100.num <=3
)
SELECT CAST('2015-01-01' AS DATETIME) + YearDay AS YearDate
FROM cteDays
WHERE YEAR(CAST( CAST('2015-01-01' AS DATETIME) + YearDay AS DATETIME)) = 2015
答案 2 :(得分:0)
这样的事情也可以起作用:
declare @count int = 0
while (@count < 365)
begin
--make this the insert
select DATEADD(DD, @count, getdate())
set @count = @count + 1
end
不确定这将适用于哪种背景......这是非常基本的,但如果这是一次性事件,那就无所谓了。