Question

您好我之前已经问过这个问题，但可能会说得对希望有人能帮助我

我正在尝试获取一个SQLite查询来计算Rolling TimeFrame中值的出现并返回一个不同的计数

我的数据看起来像这样

--------- ---------- DATA

TimeStamp         UserName   
2015-01-12 06:07:00     JamesG    
2015-01-12 06:07:00     JohnH
2015-01-12 06:10:00     JohnH
2015-01-12 06:10:00     James
2015-01-12 06:10:00     Dean
2015-01-12 06:10:00     Alicia
2015-01-12 06:12:00     Ann
2015-01-12 06:12:00     Dean
2015-01-12 06:12:00     JohnH

这是我想要的结果

Result                      count
"2015-01-12 06:07:00"         2
"2015-01-12 06:10:00"         4
"2015-01-12 06:12:00"         3

使用我当前的选择我得到一个结果，但它不考虑时间戳，它产生5分钟间隔

WITH RECURSIVE
min_time(t) AS (
SELECT datetime((strftime('%s',
(SELECT  MIN(TimeStamp)
FROM ConcurrentUsers)
) / 300) * 300,
'unixepoch')
),
max_time(t) AS (
SELECT datetime((strftime('%s',
(SELECT  MAX(TimeStamp)
FROM ConcurrentUsers)
) / 300) * 300,
'unixepoch')
),
intervals(t) AS (
SELECT t FROM min_time
UNION ALL
SELECT datetime(t, '+5 minutes')
FROM intervals
WHERE t <= (SELECT t FROM max_time)
)
SELECT t AS interval,
(SELECT COUNT(Distinct(strftime('%M',TimeStamp)))
FROM ConcurrentUsers
WHERE TimeStamp < datetime(intervals.t, '+5 minutes') AND TimeStamp >= intervals.t AS Count
FROM intervals where interval >= date('now')
ORDER BY date(interval) DESC

任何帮助将不胜感激。

我想我找到了解决方案

WITH C AS (SELECT DISTINCT TimeStamp FROM ConcurrentUsers)
SELECT Count(Distinct(UserName))TheCount,TimeStamp FROM ConcurrentUsers where TimeStamp >= date('now') 
Group by TimeStamp
ORDER BY date(TimeStamp) DESC

SQLite滚动TimeStamp计数

0 个答案: