Question

我使用浮潜来构建一个嵌入式Web服务器，它从客户端接收某种数据，以生成QR码。 QR码（保存为图像）必须显示在客户端，以便客户端捕获。问题是我无法显示它！我在嵌入式服务器中使用了HTML代码，如下所示：

<html>
<body>
<img src = QR.jpg> 
</img>
</body>
</html>

我得到的只是一个内有X的小盒子。这是我的C ++代码：

#pragma hdrstop
#pragma argsused

#include <snorkel.h>
#include <tchar.h>
#include <stdio.h>
#include <stdlib.h>

call_status_t index_htm(snorkel_obj_t http,     /*read environment from    this object */
        snorkel_obj_t outstream)  /* write data to the output stream   */
  {
   if (snorkel_printf (outstream, "<html><body><img src=QR4.jpg alt=QRcode  width=178 height=178>" //width=100% height=100% alt=QRcode>" // alt=QRcode width=178 height=178>"
                               "</img></body></html>\r\n")== SNORKEL_ERROR)
     return HTTP_ERROR;

   return HTTP_SUCCESS;
   }

void syntax (char *pszProg)
    {
     fprintf (stderr, "syntax error:\n");
     fprintf (stderr, "%s [-p <port>]\n", pszProg);
     exit (1);
    }

void main (int argc, char *argv[])
 {
  int i = 1;
  int port = 8888;
  snorkel_obj_t http = 0;
  char szExit[10];
  for (; i < argc; i++)
  {
   if (argv[i][0] == '-' || argv[i][0] == '/')
     {
      char carg = argv[i][1];
      switch (carg)
       {
        case 'p':          /* port number */
        port = atoi (argv[i + 1]);
        i++;
        break;
        default:
        syntax (argv[0]);
        break;
        }
      }
   }

/*
 *
 * initialize API
 *
 */
 if (snorkel_init () != SNORKEL_SUCCESS)
  {
    perror ("could not initialize snorkel\n");
    //exit (1);
  }
/*
 *
 * create a server object
 *
 */
 http = snorkel_obj_create (snorkel_obj_server, 5,     /* number of handler     threads to create */
                             NULL       /*     directory containing index.html     */);
 //or i can put "/Users/rania/Documents/images"
  if (!http)
   {
     perror ("could not create http server\n");
     //exit (1);
   }

/*
 *
 * create a listener
 *
 */
if (snorkel_obj_set (http,    /* server object */
                  snorkel_attrib_listener, /*  attribute   */
                  port,    /* port number */ 
                  0 /* SSL support */ )
                  != SNORKEL_SUCCESS)
      {
       fprintf (stderr, "could not create listener\n");
       snorkel_obj_destroy (http);
       //exit (1);
      }

 /*
  *
  * overload the URL index.html
  *
  */
     //THIS GENERATES AN EMPTY BOX WITH NO QR CODE
     //============================================
 if (snorkel_obj_set (http,    // server object
                 snorkel_attrib_uri,      // attribute   type
                 GET,     // method
                 "/index.html",   // url
                 encodingtype_text, index_htm) != SNORKEL_SUCCESS)

         {
           perror ("could not overload index.html");
           snorkel_obj_destroy (http);
           //exit (1);
          }
if (snorkel_obj_set(http, snorkel_attrib_ipvers, IPVERS_IPV4, SOCK_SET) != SNORKEL_SUCCESS)
        {
          fprintf (stderr, "error could not set ip version\n");
          //exit (1);
        }

 fprintf (stderr, "\n\n[HTTP] starting embedded server\n");
 if (snorkel_obj_start (http) != SNORKEL_SUCCESS)
   {
    perror ("could not start server\n");
    snorkel_obj_destroy (http);
    //exit (1);
    }

/*
 *
 * do something while server runs
 * as a separate thread
 *
 */
  fprintf (stderr, "\n[HTTP] started.\n\n"
                 "--hit enter to terminate--\n");
  fgets (szExit, sizeof (szExit), stdin);

  fprintf (stderr, "[HTTP] bye\n");

 /*
  *
  * graceful clean up
  *
  */
  snorkel_obj_destroy (http);
  exit (0);
  }

我刚刚读到要用HTML显示图像，我们必须将图像转换为DATA URL（BASE64），并且有很多在线转换器网站可以做到这一点。但问题是我的项目不使用静态QR码，它会为每个客户生成不同的QR码。此外，我的图像大小比这些在线转换器显示的图像大。

那么，有什么方法可以使用C ++以编程方式将这些图像转换为DATA URI（BASE64）？或者有什么方法可以显示我的QR码而不转换它？

我几个月来一直在努力解决这个问题，请帮忙！

最诚挚的问候。拉尼娅

如何在HTML中显示QRcode图像？

0 个答案: