将字符串转换为长力关闭app

时间:2015-01-25 11:58:49

标签: android string long-integer

我正在编写一个应用程序,需要将在文本字段中输入的字符串转换为long,但是当我运行应用程序时,它强制关闭,会出现什么问题?

应用程序很简单,只需输入在文本字段中输入的值,当用户按下按钮时,它会将此值的倒计时开始为0.(回归计时器)

有代码:

private CountDownTimer countDownTimer;
private boolean timerStarted = false;
private Button buttonStart;
public TextView textView;

private final long interval = 1 * 1000;
long tempTempo2;
long minutos4;

@Override
public void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_cronometro);

    EditText tempTempo = (EditText) findViewById(R.id.tempo);
    minutos4 = Long.parseLong(tempTempo.getText().toString());
    tempTempo2 = Long.valueOf(minutos4);


    buttonStart = (Button) this.findViewById(R.id.button);
    buttonStart.setOnClickListener(this);
    textView = (TextView) this.findViewById(R.id.textView);
    countDownTimer = new CountDownTimerActivity(minutos4, interval);
    textView.setText(textView.getText() + String.valueOf(minutos4/1000));
}

1 个答案:

答案 0 :(得分:0)

对于字符串来说,重要的是长类型,即其中没有"\n" or spaces。首先尝试修剪字符串以除去其他字符,然后转换为long。