Question

我有一个从mysql数据库中提取数据的php页面。我选择了月份和年份，它应该显示我需要的数据，但当年份更改为2015年时，我发现它只显示2014年的数据。这是代码和URL字符串

$colname_Recordset1 = "-1";
if (isset($_GET['Month'])) {    
  $colname_Recordset1 = $_GET['Month'];

}


mysql_select_db($database_hk, $hk);<br>
$query_Recordset1 = sprintf("SELECT * FROM inventory WHERE `Month` = %s", GetSQLValueString($colname_Recordset1, "text"));<br>
$Recordset1 = mysql_query($query_Recordset1, $hk) or die(mysql_error());
<br>$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
?>

我能够手动执行此操作的唯一方法是将代码更改为此<

$query_Recordset1 = sprintf("SELECT * FROM inventory WHERE `Month` = %s AND year = '2015'", GetSQLValueString($colname_Recordset1, "text"));

我希望通过2个选择下拉菜单来设置月份和年份的值

<form method="get" name="form">
<table width="70%" border="0" align="left" cellpadding="0" cellspacing="0">
  <caption>
  <br>
  </caption>
  <tr>
    <th colspan="4" align="center" scope="col"><h3>Inventory 
      <label for="month">Month:</label>
      <select name="Month" id="Month">
        <option>Select</option>
        <option value="January">January</option>
        <option value="February">February</option>
        <option value="March">March</option>
        <option value="April">April</option>
        <option value="May">May</option>
        <option value="June">June</option>
        <option value="July">July</option>
        <option value="August">August</option>
        <option value="September">September</option>
        <option value="October">October</option>
        <option value="November">November</option>
        <option value="December">December</option>
    </select>
      <label for="year">Select:</label>
      <select name="year" id="year">
        <option>Year</option>
        <option value="2014">2014</option>
        <option value="2015">2015</option>
        <option value="2016">2016</option>
        <option value="2017">2017</option>
        <option value="2018">2018</option>
        <option value="2019">2019</option>
        <option value="2020">2020</option>
      </select>
      <input type="submit" name="submit" id="submit" value="View">
</table>

按下查看按钮后的URL是 example.com/inventory_view.php?Month=January&year=2015&submit=View

我希望你能提供帮助感谢

Answer 1

你自己给出了答案。如果您没有通过年份，则无论年份如何，您都会获得特定月份的所有数据。所以也抓住你的$_GET变量的年份并像你一样扩展你的查询，但只是像月份那样变量。

PHP库存数据库

1 个答案: