我非常擅长提升::精神。我想将一串逗号分隔的对象解析为std :: vector(与教程中类似)。字符串可以是不同的类型(在编译时已知):整数,如"1,2,3"
,字符串"Apple, Orange, Banana"
等。
我想为所有类型提供统一的界面。
如果我解析单个元素,我可以使用auto_
表达式。
是否有可能与向量具有类似的接口?
我可以定义一个规则,给定一个模板参数,实际上可以解析这个向量吗?
这是一个简单的示例代码(由于最后一次调用phrase_parse而无法编译):
#include <boost/config/warning_disable.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix_core.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/phoenix_stl.hpp>
#include <iostream>
#include <vector>
#include <boost/spirit/include/qi_auto.hpp>
namespace qi = boost::spirit::qi;
namespace ascii = boost::spirit::ascii;
namespace phoenix = boost::phoenix;
using qi::auto_;
using qi::phrase_parse;
using ascii::space;
using phoenix::push_back;
int main()
{
std::string line1 = "3";
std::string line2 = "1, 2, 3";
int v;
std::vector<int> vector;
typedef std::string::iterator stringIterator;
stringIterator first = line1.begin();
stringIterator last = line1.end();
namespace qi = boost::spirit::qi;
namespace ascii = boost::spirit::ascii;
bool r1 = qi::phrase_parse( first,
last,
qi::auto_,
ascii::space,
v );
first = line2.begin();
last = line2.end();
//The following call is wrong!
bool r2 = qi::phrase_parse( first,
last,
// Begin grammar
(
qi::auto_[push_back(phoenix::ref(vector), qi::_1)]
>> *(',' >> qi::auto_[push_back(phoenix::ref(vector),qi::_1)])
),
// End grammar
ascii::space,
vector);
return 0;
}
更新
我找到了一个解决方案,在解析之前已知向量的大小。另一方面,我不能使用语法*( ',' >> qi::auto_ )
。
#include <boost/spirit/include/qi.hpp>
namespace qi = boost::spirit::qi;
int main()
{
std::string s = "1, 2, 3";
std::vector<int> vector;
//This works
qi::phrase_parse(s.begin(), s.end(), qi::auto_ >> ',' >> qi::auto_ >> ',' >> qi::auto_ , qi::blank, vector);
//This does not compile
qi::phrase_parse(s.begin(), s.end(), qi::auto_ >> *( ',' >> qi::auto_ ) , qi::blank, vector);
for(int i = 0; i < vector.size() ; i++)
std::cout << i << ": " << vector[i] << std::endl;
return 0;
}
此外,使用auto_
,我无法解析一个字符串。是否可以定义e模板函数,其中语法可以通过模板参数推导出来?
template< typename T >
void MyParse(std::string& line, std::vector<T> vec)
{
qi::phrase_parse( line.begin(),
line.end(),
/*
How do I define a grammar based on T
such as:
double_ >> *( ',' >> double_ ) for T = double
+qi::alnum >> *( ',' >> +qi::alnum ) for T = std::string
*/,
qi::blank,
vec);
}
答案 0 :(得分:2)
auto_
支持开箱即用的容器属性:
<强> Live On Coliru 强>
std::istringstream iss("1 2 3 4 5; 6 7 8 9;");
iss.unsetf(std::ios::skipws);
std::vector<int> i;
std::vector<double> d;
if (iss >> qi::phrase_match(qi::auto_ >> ";" >> qi::auto_, qi::space, i, d))
{
for (auto e:i) std::cout << "int: " << e << "\n";
for (auto e:d) std::cout << "double: " << e << "\n";
}
打印
int: 1
int: 2
int: 3
int: 4
int: 5
double: 6
double: 7
double: 8
double: 9
所以你基本上可以使用','
作为队长编写模板函数。我更喜欢operator%
变体。
template<typename Container>
void MyParse(std::string const& line, Container& container)
{
auto f(line.begin()), l(line.end());
bool ok = qi::phrase_parse(
f, l,
qi::auto_ % ',', qi::blank, container);
if (!ok || (f!=l))
throw "parser error: '" + std::string(f,l) + "'"; // FIXME
}
template<typename Container>
void MyParse(std::string const& line, Container& container)
{
auto f(line.begin()), l(line.end());
bool ok = qi::phrase_parse(
f, l,
qi::auto_, qi::blank | ',', container);
if (!ok || (f!=l))
throw "parser error: '" + std::string(f,l) + "'"; // FIXME
}
string
案例(和其他人):如果Spirit不能“推导”元素类型(任何东西都可以被解析为字符串),那么只需要一个知道如何解析元素类型的可选解析器/语法?
template<typename Container, typename ElementParser = qi::auto_type>
void MyParse(std::string const& line, Container& container, ElementParser const& elementParser = ElementParser())
{
auto f(line.begin()), l(line.end());
bool ok = qi::phrase_parse(
f, l,
elementParser % ",", qi::blank, container);
if (!ok || (f!=l))
throw "parser error: '" + std::string(f,l) + "'"; // FIXME
}
现在,它解析字符串就好了:
std::vector<int> i;
std::set<std::string> s;
MyParse("1,22,33,44,15", i);
MyParse("1,22,33,44,15", s, *~qi::char_(","));
for(auto e:i) std::cout << "i: " << e << "\n";
for(auto e:s) std::cout << "s: " << e << "\n";
打印
i: 1
i: 22
i: 33
i: 44
i: 15
s: 1
s: 15
s: 22
s: 33
s: 44
<强> Live On Coliru 强>
#include <boost/spirit/include/qi.hpp>
#include <iostream>
namespace qi = boost::spirit::qi;
template<typename Container, typename ElementParser = qi::auto_type>
void MyParse(std::string const& line, Container& container, ElementParser const& elementParser = ElementParser())
{
auto f(line.begin()), l(line.end());
bool ok = qi::phrase_parse(
f, l,
elementParser % ",", qi::blank, container);
if (!ok || (f!=l))
throw "parser error: '" + std::string(f,l) + "'"; // FIXME
}
#include <set>
int main()
{
std::vector<int> i;
std::set<std::string> s;
MyParse("1,22,33,44,15", i);
MyParse("1,22,33,44,15", s, *~qi::char_(","));
for(auto e:i) std::cout << "i: " << e << "\n";
for(auto e:s) std::cout << "s: " << e << "\n";
}