在appDevDebugProjectContainer.php中找不到Symfony 2错误类

时间:2015-01-24 12:44:03

标签: php symfony

我想添加带有安全上下文的表单服务,如下所示:

namespace Infogold\AccountBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
use Symfony\Component\Security\Core\SecurityContext;
use Doctrine\ORM\EntityRepository;

class KonsultantType extends AbstractType {

     protected $user;

    public function __construct(SecurityContext $user) {


        $this->user = $user;
    }
 public function buildForm(FormBuilderInterface $builder, array $options) {
    -
    -
    -
    -
    -
    -
  public function getName() {
        return 'konsultanci_form';
    }

在服务中:

parameters:
#    infogold_account.example.class: Infogold\AccountBundle\Example

services:

   form.type.konsultanci_form:
       class:  Infogold\AccountBundle\Form\KonsulantType
       arguments: ['@security.context'] 
       tags:
            - { name: form.type, alias: konsultanci_form }  

我收到了这个错误:

FatalErrorException:错误:在D:\ xampp \ htdocs \ symfony4 \ app \ cache \ dev \ appDevDebugProjectContainer.php第718行找不到类'Infogold \ AccountBundle \ Form \ KonsulantType'

718行是:

protected function getForm_Type_KonsultanciFormService()
    {
        return $this->services['form.type.konsultanci_form'] = new \Infogold\AccountBundle\Form\KonsulantType($this->get('security.context'));
    }

我犯了错误?

1 个答案:

答案 0 :(得分:1)

正如我所说,这是班级名称的错误。它是KonsultantType而不是KonsulantType

尝试:

parameters:
#    infogold_account.example.class: Infogold\AccountBundle\Example

services:

   form.type.konsultanci_form:
       class:  Infogold\AccountBundle\Form\KonsultantType
       arguments: ['@security.context'] 
       tags:
            - { name: form.type, alias: konsultanci_form }