Question

我正在尝试禁用用户先前选择的按钮

void pracownik2::on_pushButton_4_clicked(){

this->setWindowTitle("EKRAN");
QWidget *centralWidget = new QWidget;
        int licznik=1;
        QString licz;
        //QString kolumny = ui->lineEdit->text();
        //QString wiersze = ui->lineEdit_2->text();
        miejsca2 = ui->lineEdit_3->text().toInt();
        //QPushButton *button[wiersze.toInt()][kolumny.toInt()];
        QPushButton *button[3][6];

        QGridLayout *controlsLayout = new QGridLayout;
        for(int i=0;i<3;i++)
        {
            for(int j=0;j<6;j++)
            {
                    licz = QString::number(licznik);
                    licznik++;
                    button[i][j] = new QPushButton(licz);
                    button[i][j]->setCheckable(1);
                        if(tab[i][j]==1)
                            button[i][j]->setEnabled(false);
                    controlsLayout->addWidget(button[i][j], i, j);
            }
        }

        QPushButton *okej = new QPushButton("Zatwierdź");
        QPushButton *anul = new QPushButton("Anuluj");

        controlsLayout->addWidget(okej, 3, 0);
        controlsLayout->addWidget(anul, 3, 1);

        controlsLayout->setHorizontalSpacing(0);
        controlsLayout->setVerticalSpacing(0);
        centralWidget->setLayout(controlsLayout);

        setCentralWidget(centralWidget);



        for(int i=0;i<3;i++)
        {
            for(int j=0;j<6;j++)
            {
                    connect(button[i][j],SIGNAL(toggled(bool)),this,SLOT(tescik(bool)));
            }
        }



        connect(anul,SIGNAL(clicked()),this,SLOT(close()));

        connect(okej,SIGNAL(clicked()),this,SLOT(okay2()));}

void pracownik2::tescik(bool t){
    if (t)
{
    tab[i][j]=1;
    miejsca++;
}
else
{
    tab[i][j]=0;
    miejsca--;
}}

但我的＆＃39; tescik＆＃39;功能并不知道＆＃39; i＆＃39;和＆＃39; j＆＃39;是的，项目不会编译，我的问题是如何使数组中的选中按钮设置值1并取消选中将其恢复为0.我想我必须编辑＆＃39; connect＆＃39;但我不知道如何

@EDIT 我正在尝试制作这一行

connect(button[i][j],SIGNAL(toggled(bool)),this,SLOT(tescik(bool,int i,int j)));

传递＆＃39;我＆＃39;和＆＃39; j＆＃39;当前按钮的功能，但它没有工作

Answer 1

您无法连接

connect(button[i][j],SIGNAL(toggled(bool)),this,SLOT(tescik(bool,int i,int j)));

因为toggled如何知道i,j的哪些值传递给tescik？

然而，你可以在QPushButtons上编写一个包装器，这样你就可以使用QSignalMapper将它们的toggled(bool)信号连接到这个包装器的单个插槽toggled( int, int)。然后你可以在这样的包装器中管理所有这些逻辑：

class ButtonHelperEntry
{
public:
    int i_;
    int j_;
    QPushButton* button_;
}

void ButtonHelper::initialize( const std::vector<
                                   QSharedPointer<ButtonHelperEntry> >& entries)
{
    entries_ = entries;
    mapper_.reset(new QSignalMapper(this));
    EntriesIterator it = entries_.begin();

    while ( it!=entries_.end())
    {
       connect(( *it)->button_, SIGNAL( toggled(bool)), mapper_.data(), 
                                                                   SLOT(map()));
       mapper_->setMapping( ( *it)->button_, (int)( *it)->i_, (int)( *it)->j_);
       it++;
       i++;
    }
    connect( mapper_.data(), SIGNAL( mapped(int,int)), 
                             this, SIGNAL( toggled(int,int)));
    connect( this, SIGNAL( toggled(int)), this, SLOT( updateValue(int)));
}

Answer 2

我会将i和j设置为每个按钮的属性：

...
button[i][j]->setProperty("i", i);
button[i][j]->setProperty("j", j);
...

然后在tescik（）中获取发件人并加载i和j：

void pracownik2::tescik(bool t) {
   QObject * pSender = sender();
   int i = pSender->property("i").toInt();
   int j = pSender->property("j").toInt();

   if (t) {
   ...

Qt禁用动态按钮

2 个答案: