Question

我正在尝试检查MYSQL用户是否存在。这是我所拥有的。我沮丧地从输出中捕获答案。

 #!/bin/bash
echo -e "What is the MYSQL username called"
    read DBUSER
    if [ -z "$DBUSER" ]
    then
    exit

    mysql -uUSER -pPASS -e "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')";

    if 
    yes
    do this
    else
    do this

这是我得到的输出

+-----------------------------------------------------+
| EXISTS(SELECT 1 FROM mysql.user WHERE user = 'bob') |
+-----------------------------------------------------+
|                                                   1 |
+-----------------------------------------------------+

任何人都可以帮忙吗

Answer 1

非常感谢你的帮助。这是最终的结果。

需要-sse

RESULT_VARIABLE="$(mysql -uUSER -pPASS -sse "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')")"

if [ "$RESULT_VARIABLE" = 1 ]; then
echo "TRUE"
else
  echo "FALSE"
fi

Answer 2

将结果分配给变量可以这样做：

RESULT_VARIABLE="$(mysql -uUSER -pPASS -se "SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER')")"

你也可以在MySQL中使用别名，btw。

SELECT EXISTS(SELECT 1 FROM mysql.user WHERE user = '$DBUSER') AS does_it_exist

试图检查bash脚本中是否存在Mysql用户

2 个答案: