Question

我正在制作一个查询，让我了解客户的习惯，例如 - 平均花费，预订数量等。

我当前的查询看起来像

SELECT email, 
   Avg(amount_paid) AS avg_paid, 
   Count(*)         AS no_times_booked 
FROM   bookings
GROUP  BY email

这为我提供了电子邮件，平均支出和预订次数

我的表看起来像

email           | amount_paid | booking_date
email@email.com | 50.00       | 2010-01-13
email@email.com | 50.00       | 2010-01-13
email@email.com | 50.00       | 2010-01-13

如何调整查询以获得每月平均预订次数？

所以我的结果如下所示，最终我的用户数是每个用户一个平均数 - 如果他们只在下个月预订一次，他们的平均数就会下降。

或者换句话说，我试图标记普通客户 - 每月或更高的预订将是常规的。

email           | avg_spend | number_bookings | avg_bookings_per_month
email@email.com | 50.00     | 3               | 3

Answer 1

您拥有大部分内容，但为了获得每月的平均预订量，您需要嵌套查询。最内部的查询将基于电子邮件帐户的分组和预订的月份/年份（以免混淆2014年1月和2015年1月的数字）。

SELECT 
      PreAgg.email,
      sum( PreAgg.overallPaid ) as TotalPaid,
      sum( PreAgg.timesBooked ) as TimesBooked,
      sum( PreAgg.overallPaid ) / sum( PreAgg.timesBooked ) as OverallAvgPd,
      Avg( PreAgg.ThisMthYrAvgPd ) as AvgPerMthYr
   FROM   
      ( SELECT 
              email,
              year( booking_date ) as bkYear,
              month( booking_date ) as bkMth
              sum( amount_paid ) as overallPaid,
              count( * ) as timesBooked,
              avg( amount_paid ) as ThisMthYrAvgPd
           from 
              bookings
           group by
              email
              year( booking_date ),
              month( booking_date ) ) PreAgg
   GROUP  BY 
      PreAgg.email

然而，这将获得大部分，它不会得到它，因为我们没有查询所代表的时间段的上下文。每月/每年的平均值就是这个数字。但是如果你知道你要查询的时间段（例如：2014年全年），那么你需要计算每月平均值12来获得更准确的每月费率。有人可以在一个月内旅行3次，然后在6个月内旅行，然后再旅行2次。总共5次，但只有2个月的活动。因此，您需要如何量化“常规”访客/访客身份。如果在12个月中预订的2个月与12个月中的5个预订总数相比给出了完全不同的分数答案。

Answer 2

感谢您的帮助，继续这个

//如果在过去12个月内预订的次数相等或高于他们预订的预订月份的唯一数量，则他们是普通的预订者。

SELECT email, 
       Avg(amount_paid)                AS avg_paid, 
       Count(*)                        AS no_times_booked, 
       Count(DISTINCT( Month(added) )) AS unique_months 
FROM   bookings
WHERE  added >= Now() - INTERVAL 1 year 
GROUP  BY email

Answer 3

使用您的查询进行测试

      SELECT
YEAR(booking_date) AS YEAR,
CASE 
   WHEN  MONTH(booking_date) = 1 
    THEN SUM(amount_paid)/31 
ELSE 0 END JAN,
CASE 
   WHEN  MONTH(booking_date) = 2 
    THEN SUM(amount_paid)/28 
ELSE 0 END FEB,
CASE 
   WHEN  MONTH(booking_date) = 3 
    THEN SUM(amount_paid)/31 
ELSE 0 END MARCH,
CASE 
   WHEN  MONTH(booking_date) = 4 
    THEN SUM(amount_paid)/30 
ELSE 0 END APRL,
CASE 
   WHEN  MONTH(booking_date) = 5 
    THEN SUM(amount_paid)/31 
ELSE 0 END MAY,
CASE 
   WHEN  MONTH(booking_date) = 6 
    THEN SUM(amount_paid)/30 
ELSE 0 END JUNE,
CASE 
   WHEN  MONTH(booking_date) = 7 
    THEN SUM(amount_paid)/31 
ELSE 0 END JULY,
CASE 
   WHEN  MONTH(booking_date) = 8 
    THEN SUM(amount_paid)/31 
ELSE 0 END AUG,
CASE 
   WHEN  MONTH(booking_date) = 9 
    THEN SUM(amount_paid)/30 
ELSE 0 END SEP,
CASE 
   WHEN  MONTH(booking_date) = 10 
    THEN SUM(amount_paid)/31 
ELSE 0 END OCTOBER,
CASE 
   WHEN  MONTH(booking_date) = 11 
    THEN SUM(amount_paid)/30 
ELSE 0 END NOV,
CASE 
   WHEN  MONTH(booking_date) = 12 
    THEN SUM(amount_paid)/31 
ELSE 0 END DECE

FROM bookings
WHERE  booking_date >= NOW() - INTERVAL 4 YEAR 
GROUP BY 1;

mysql查询每月平均预订量

3 个答案: