Question

我有一个MySQL查询：

select * 
  from traffic 
 group 
    by type
     , date
     , address 
having count(date and type and address) > 3 
   and status = 0

我想选择输入相同类型，日期，有计数地址（日期和类型和地址）＆gt; 3和状态= 0的不同用户的所有详细信息。

这是表格

 traffic

slno | username | lat | longi | message | dat | time | type | address | status

上述查询有效，但如果同一用户输入的数据超过三次，我的查询会显示结果。我希望在不同的用户输入相同的流量数据时看到结果。

+==========+
| traffic  |
+==========+
| slno     | 
| username | 
| lat      | 
| longi    | 
| message  | 
| dat      | 
| time     | 
| type     | 
| address  | 
| status   |
+----------+

Answer 1

选择超过3个不同用户拥有相同流量数据的流量记录：

SELECT *
FROM `traffic`
WHERE `status` = 0
GROUP BY `type`, `date`, `address`
HAVING COUNT(DISTINCT `username`) > 3

demo

如果您想选择相应的用户：

SELECT DISTINCT t.*
FROM `traffic` t 
INNER JOIN (
  SELECT *, COUNT(DISTINCT `username`)
  FROM `traffic`
  WHERE `status` = 0
  GROUP BY `type`, `date`, `address`
  HAVING COUNT(DISTINCT `username`) > 3
) x
ON t.`type` = x.`type`
AND t.`date` = x.`date`
AND t.`address` = x.`address`

demo

Answer 2

你的意思是这样的：

select username, date, type, address
from traffic 
where status = 0
group by username, date, type, address
having count(date) > 3 
and count(type) > 3 
and count(address) > 3

如何选择不同用户过滤某些结果？

2 个答案: