Question

我使用以下语法来区分两个日期：

DATEDIFF(minute, [Dam_Date_Of_Birth], [Calf_Date_Of_Birth]) as [minutes]

此查询给出了以下结果：

如何将这些值变为年，月，日格式？

Answer 1

你也可以这样做

DECLARE @diff float = 1748160 / 24.0 / 60.0
Declare @date datetime = convert(datetime, @diff);
Select DatePart(yy, @date) - 1900 as Years, DatePart(mm, @date) - 1 Months, DatePart(dd, @diff) - 1 Days

或者您只需将您的会议记录添加到1900年1月1日＆＃39;得到相同的结果：

Declare @date datetime = DateAdd(minute, 1748160, '1 Jan 1900');
Select DatePart(yy, @date) - 1900 as Years, DatePart(mm, @date) - 1 Months, DatePart(dd, @date) - 1 Days

所以你可以这样使用：

DECLARE @dtStartDate date = '01 Jan 2015'
DECLARE @dtEndDate date = '11 Jan 2015'
Declare @date datetime = DateAdd(minute, DATEDIFF(minute, @dtStartDate, @dtEndDate), '1 Jan 1900');
Select DatePart(yy, @date) - 1900 as Years, DatePart(mm, @date) - 1 Months, DatePart(dd, @date) - 1 Days

Answer 2

参考this

DECLARE @nMonth INT, @nYear INT, @mm INT, @dd INT, @getdd int
DECLARE  @dtStartDate AS DATETIME, @dtEndDate AS datetime

SET @dtStartDate = '01/01/2015'
SET @dtEndDate = '02/11/2015'
SET @nYear = DATEDIFF(yy, @dtStartDate, @dtEndDate)
SET @mm = DATEDIFF(mm, @dtStartDate, @dtEndDate)
SET @dd = DATEDIFF(dd, @dtStartDate, @dtEndDate)
SET @nMonth = ABS(DATEDIFF(mm, DATEADD(yy, @nYear, @dtStartDate), @dtEndDate))
SET @getdd = ABS(DATEDIFF(dd, 
                          DATEADD(mm, 
                                  DATEDIFF(mm, 
                                           DATEADD(yy, @nYear, @dtStartDate), 
                                           @dtEndDate), 
                                  DATEADD(yy, @nYear, @dtStartDate)), 
                          @dtEndDate))

SELECT  Convert(varchar(10),@nYear) + ' year ' + 
        Convert(varchar(10),@nMonth) + ' month '  + 
        Convert(varchar(10),@getdd) + ' day(s)'

输出： 0 year 1 month 10 day(s)

Answer 3

解决问题366天：

declare @st_date date = '2318-01-01';
declare @end_date date = '2417-12-31';
select datepart(yyyy,dateadd(year,(year(@st_date))%4+((year(@st_date)+100)%400/100)*100,cast(0 as datetime)) + datediff(day,@st_date,@end_date) ) - 
(1900+(year(@st_date))%4+(((year(@st_date)+100)%400/100)*100)) as year
,datepart(mm,dateadd(year,(year(@st_date))%4+((year(@st_date)+100)%400/100)*100,cast(0 as datetime)) + datediff(day,@st_date,@end_date) ) - 1 as month
,datepart(dd,dateadd(year,(year(@st_date))%4+((year(@st_date)+100)%400/100)*100,cast(0 as datetime)) + datediff(day,@st_date,@end_date) ) - 1 as day

输出 99 year 11 month 30 day

总月份：

select (datepart(yyyy,dateadd(year,(year(@st_date))%4+((year(@st_date)+100)%400/100)*100,cast(0 as datetime)) + 
datediff(day,@st_date,@end_date) ) - (1900+(year(@st_date))%4+(((year(@st_date)+100)%400/100)*100))) * 12 +
datepart(mm,dateadd(year,(year(@st_date))%4+((year(@st_date)+100)%400/100)*100,cast(0 as datetime)) + 
datediff(day,@st_date,@end_date) ) - 1 as totalmonth

输出 1199 totalmonth

Answer 4

更新：

DECLARE
    @yearMin DATE = '1983.01.01' ,
    @yearMax DATE = '2014.12.23' ,
    @years INT ,
    @months INT ,
    @days INT;

SELECT
    @years = DATEDIFF(YEAR, @yearMin, @yearMax) ,
    @months = DATEDIFF(MONTH, @yearMin, @yearMax) - @years * 12 ,
    @days = DATEDIFF(DAY, @yearMin,
                     DATEADD(MONTH, -@months,
                             DATEADD(YEAR, -@years, @yearMax)))

SELECT
    @years AS Years ,
    @months AS Months ,
    @days AS Days;

如何在sql中将时间跨度转换为年，月和日

4 个答案: