Question

为什么firstId不等于secondId？ firstId是错误的，secondId是正确的。

如何“强制”getIdentifier搜索正确的search_button？

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    getMenuInflater().inflate(R.menu.menu_main, menu);
    MenuItem searchItem = menu.findItem(R.id.action_search);
    SearchView searchView = (SearchView) MenuItemCompat.getActionView(searchItem);

    int firstId = getResources().getIdentifier("android:id/search_button", null, null);
    int secondId = recursiveLoopChildren(searchView, "search_button").getId();     

    return true;
}

public View recursiveLoopChildren(ViewGroup p_parent, String p_resourceName) {
    View view = null;

    for (int i = p_parent.getChildCount() - 1; i >= 0; i--) {
        final View child = p_parent.getChildAt(i);
        if (child instanceof ViewGroup) {
            View returnedChild = recursiveLoopChildren((ViewGroup) child, p_resourceName);
            if(returnedChild != null) {
                view = returnedChild;
                break;
            }
        } else {
            String entryName = getResources().getResourceEntryName(child.getId());
            if (child != null && entryName.equals(p_resourceName)) {
                view = child;
                break;
            }
        }
    }

    return view;
}

Answer 1

像这样调用getIdentifier（）：

int firstId = getResources().getIdentifier("search_button", "id", getPackageName());

然后它应该返回正确的id。

Answer 2

试试这个

final View child = p_parent.getChildAt(i - 1);

如果不起作用..试试这个条件..

for (int i = p_parent.getChildCount(); i > 0; i--)

按名称获取资源ID返回“错误”ID

2 个答案: