我正在尝试在多列上使用数据透视表。目前，我只用一列即可实现这一目标。我当前的方法返回：
Membership Item1
DO1 400
Neither 21
Plan A 69
Plan B 53
但这是我想要实现的目标：
Membership Item1 Item2 Item3 Item3 Item4 Item5
DO1 30 300 25 14 10 144
Neither 35 250 30 30 5 125
Plan A 50 100 25 25 5 254
Plan B 100 25 15 25 4 123
这是我的代码
WITH CTE_SQL
AS
(
SELECT CaseId
,Item1 AS Number1
,[Membership] -- ,Item2 AS Number2,Item3 AS Number3,Item4 AS Number4,Item5 AS Number5
FROM TABLE1
WHERE [Membership] IS NOT NULL
)
SELECT [Membership]
,Item1 --,Item2--,Item3 AS 'Item3',Item4 AS 'Item4',Item5 AS 'Item5'
FROM
(
SELECT CaseId
,Number1
,[Membership] --,[Item2],[Item3],[Item4],[Item5]
FROM CTE_SQL
) AS p
PIVOT
(
COUNT(CaseId)
FOR Number1 IN (Item1)
) AS pvt
ORDER BY [Membership]
有什么见解？ 更新此处是表架构
ColumnName DataType Allow Nulls
.......... ........ ...........
CaseId nvarchar(50) No
Membership nvarchar(50) Yes
Item1 nvarchar(50) Yes
Item2 nvarchar(50) Yes
Item3 nvarchar(50) Yes
Item4 nvarchar(50) Yes
Item5 nvarchar(50) Yes
所以这是我上一次的更新。这是我的源数据：
CREATE TABLE TABLE1
(CASENumber NVARCHAR(50),Membership NVARCHAR(50),Item1 NVARCHAR(50),Item2 NVARCHAR(50),Item3 NVARCHAR(50),Item4 NVARCHAR(50),Item5 NVARCHAR(50))
INSERT INTO TABLE1
SELECT 'Case001', 'D01','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case002', 'D01','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case003', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case004', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case001', 'PlanA','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case002', 'PlanA','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case003', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case004', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case001', 'D01','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case002', 'D01','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case003', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case004', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case001', 'PlanA','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case002', 'PlanA','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case003', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case004', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case003', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case004', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case001', 'D01','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case002', 'D01','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case003', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case004', 'Neither','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case005', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case001', 'PlanB','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case002', 'D01','Gold','Silver','Diamond','Steel','Wood'
UNION ALL
SELECT 'Case003', 'Neither','Gold','Silver','Diamond','Steel','Wood'
在这里，我的代码和输出到目前为止一直困在我们身上：
WITH CTE_SQL
AS
(
SELECT CASENumber,Item1 AS Number1,[Membership]--,Item2 AS Number2,
Item3 AS Number3,Item4 Number4,Item5 AS Number5
FROM dbo.TABLE1
WHERE [Membership] IS NOT NULL
)
SELECT Membership,Gold as 'Item1' --,Item2--,Item3 AS 'Item3',
Item4 AS 'Item4',Item5 AS 'Item5'
FROM
(
SELECT CaseNumber,Number1,Membership--,[Item2],[Item3],[Item4],[Item5]
FROM CTE_SQL
) AS p
PIVOT
(
COUNT(CASENumber)
FOR Number1 in(Gold)
) as pvt
当前输出
Membership Item1
......... .....
D01 7
Neither 9
PlanA 4
PlanB 13
预期输出
Membership Item1 Item2 Item3 Item4 Item5
.......... ..... ..... ..... ..... .....
D01 7 7 7 7 7
Neither 9 9 9 9 9
PlanA 4 4 4 4 4
PlanB 13 13 13 13 13
请注意，items1列下的所有元素都是黄金。这同样适用于分别为Silver，Diamond，Steel和Wood的第2-5项。
答案 0 :(得分：0)
您需要动态数据透视才能获得结果。
声明变量以获取pivot
的列 DECLARE @cols NVARCHAR (MAX)
SELECT @cols = COALESCE (@cols + ',[' + Number1 + ']', '[' + Number1 + ']')
FROM (SELECT DISTINCT Number1 FROM #TEMP) PV
ORDER BY Number1
现在转动查询
DECLARE @query NVARCHAR(MAX)
SET @query = 'SELECT * FROM
(
SELECT Membership, Number1,
-- Get the count here
COUNT(CASEID) OVER(PARTITION BY Membership,Number1) CNT
FROM #TEMP
WHERE Membership IS NOT NULL
) x
PIVOT
(
MIN(CNT)
FOR Number1 IN (' + @cols + ')
) p
ORDER BY Membership;'
EXEC SP_EXECUTESQL @query
编辑：
根据您的更新，如果您需要为每个成员计算CaseId，您可以使用以下查询
;WITH CTE AS
(
SELECT DISTINCT Membership,
COUNT(CASEID) OVER(PARTITION BY Membership) CNT
FROM TABLE1
WHERE Membership IS NOT NULL
)
SELECT Membership,CNT AS Item1,CNT AS Item2,CNT AS Item3,CNT AS Item3,CNT AS Item4,CNT AS Item5
FROM CTE
编辑2：
亲爱的朋友。这是一个简单的过程。我们可以在没有旋转的情况下完成。我们可以在PARTITION BY()中使用Sql Server方法，它会为每个CASENUMBER获得Membership的总计数。
SELECT DISTINCT [Membership],
COUNT(Item1) OVER(PARTITION BY [Membership]) AS Item1,
COUNT(Item2) OVER(PARTITION BY [Membership]) AS Item2,
COUNT(Item3) OVER(PARTITION BY [Membership]) AS Item3,
COUNT(Item4) OVER(PARTITION BY [Membership]) AS Item4,
COUNT(Item5) OVER(PARTITION BY [Membership]) AS Item5
FROM TABLE1
WHERE [Membership] IS NOT NULL
ORDER BY MEMBERSHIP
<强> RESULT
x-------------x-----------x----------x----------x---------x---------x
| Membership | Item1 | Item2 | Item3 | Item4 | Item5 |
x-------------x-----------x----------x----------x---------x---------x
| D01 | 7 | 7 | 7 | 7 | 7 |
| Neither | 9 | 9 | 9 | 9 | 9 |
| Plan A | 4 | 4 | 4 | 4 | 4 |
| Plan B | 13 | 13 | 13 | 13 | 13 |
x-------------x-----------x----------x----------x---------x---------x