Question

我在Symfony2中有一个表单，用户正在为其信用卡提交信息。表单呈现完全正常，但在提交时，我收到错误"An exception occured in driver: SQLSTATE[28000] [1045] Access denied for user 'root'@'localhost' (using password: NO)".

我的控制器操作代码：

<?php

/**
 * Class: PaymentController
 *
 * This controller is used to serve an iframe that contains a form for
 * a person's credit card information.
 *
 * @see Controller
 */
class PaymentController extends Controller
{
    /**
     * indexAction
     *
     * Display a form for a user to enter their credit card information
     *
     * @param Request $request
     */
    public function subscribeAction(Request $request)
    {
        $ccForm = new CreditCard();
        $form = $this->createForm(new CreditCardType(), $ccForm);

        //This function attempts to connect to DB on form submission 
        $form->handleRequest($request);
        //Never gets here

        if ($form->isValid()) {

        } 


        //render view here (this part works fine)
    }
}

我的问题是为什么$form->handleRequest($request)会尝试连接数据库？从堆栈跟踪看起来，Validator类调用Doctrine ORM，并尝试连接到db。我不希望它这样做，我只想将数据保存在内存中，并使用它进行一些API调用。

我的实体类中没有元数据表明Doctrine应该尝试将其保存到db。有什么想法吗？

编辑：如果我从app/config/config.yml删除学说配置，那么我可以在$form-isValid()

之后完全正确地访问我的表单对象

# Doctrine Configuration
#doctrine:
#    dbal:
#        driver:   "%database_driver%"
#        host:     "%database_host%"
#        port:     "%database_port%"
#        dbname:   "%database_name%"
#        user:     "%database_user%"
#        password: "%database_password%"
#        charset:  UTF8
#        # if using pdo_sqlite as your database driver:
#        #   1. add the path in parameters.yml
#        #     e.g. database_path: "%kernel.root_dir%/data/data.db3"
#        #   2. Uncomment database_path in parameters.yml.dist
#        #   3. Uncomment next line:
#        #     path:     "%database_path%"
#
#    orm:
#        auto_generate_proxy_classes: false
#        auto_mapping: false

Answer 1

如果您创建了一个CreditCardType()对象，它将调用您的实体，包括用于检查对象的doctrine和connection。您可以尝试在控制器中创建手册，如下所示：

public function subscribeAction(Request $request)
{
    $form = $this->createCreditCardForm();
    $form->handleRequest($request);

    if ($form->isValid()) {             
        $entity = $form->getData();
        // do what you want with the $entity
    } 
    //render view here 
}

private function createCreditCardForm()
{
    return $this->createFormBuilder()->setAction($this->generateUrl('route_here_if_needed'))
        ->setMethod('GET')
        ->add('your_field', 'type')
        ->add('submit', 'submit')
        ->getForm()
    ;
}

如果您可以成功完成此操作，则可以尝试修改类型，而无需创建CreditCardType()对象。

Answer 2

不，$form->handleRequest未明确连接到数据库，但 does fire form events 。根据{{1}}上的子表单，其中一个子表单可以连接到数据库。

Symfony2表单尝试在提交时连接到DB

2 个答案: