Question

如何使用静态资源启用charset = utf-8响应头？资源文件采用UTF-8格式，但以ISO-Western-Europe编码显示

编辑：正如评论中所说的那样是web.xml

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
  ...
  <filter>
   <filter-name>OCPsoft Rewrite Filter</filter-name>
   <filter-class>org.ocpsoft.rewrite.servlet.RewriteFilter</filter-class>
   <!-- <async-supported>true</async-supported> -->
  </filter>
  <filter>
    <filter-name>CharacterEncodingFilter</filter-name>
    <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
    <init-param>
      <param-name>encoding</param-name>
      <param-value>UTF-8</param-value>
    </init-param>
    <init-param>
      <param-name>forceEncoding</param-name>
      <param-value>true</param-value>
    </init-param>
  </filter>
  <filter>
    <filter-name>HttpMethodFilter</filter-name>
    <filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
  </filter>
  <filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
  </filter>
    <filter-mapping> 
    <filter-name>OCPsoft Rewrite Filter</filter-name> 
    <url-pattern>/*</url-pattern> 
    <dispatcher>FORWARD</dispatcher> 
    <dispatcher>REQUEST</dispatcher> 
    <dispatcher>INCLUDE</dispatcher> 
 </filter-mapping> 
  <filter-mapping>
    <filter-name>CharacterEncodingFilter</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>
  <filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>
  <filter-mapping>
    <filter-name>HttpMethodFilter</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>
  ...
</web-app>

Answer 1

您可以使用CharacterEncodingFilter（see javadoc）。

Spring mvc静态资源，带有utf-8响应头

1 个答案: