目前,如果我想避免gson从反序列化json字符串到LinkedHashMap
,我会使用以下代码
HashMap<Integer, String> map = gson.fromJson(json_string, new TypeToken<HashMap<Integer, String>>(){}.getType());
但是,我有以下课程
public static class Inventory {
public Map<Integer, String> map1 = new HashMap<Integer, String>();
public Map<Integer, String> map2 = new HashMap<Integer, String>();
}
如果我使用Inventory result = gson.fromJson(json_string, Inventory.class);
,我的Inventory
实例的类成员将为LinkedHashMap
。
如何强制对json字符串进行反序列化,让HashMap
成为类成员?
这是工作代码示例
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
import com.google.gson.reflect.TypeToken;
import java.util.HashMap;
import java.util.Map;
/**
*
* @author yccheok
*/
public class Gson_tutorial {
public static class Inventory {
public Map<Integer, String> map1 = new HashMap<Integer, String>();
public Map<Integer, String> map2 = new HashMap<Integer, String>();
}
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
{
Map<Integer, String> map= new HashMap<Integer, String>();
map.put(2, "cake");
final Gson gson = new GsonBuilder().create();
final String json_string = gson.toJson(map);
// {"2":"cake"}
System.out.println(json_string);
HashMap<Integer, String> result = gson.fromJson(json_string, new TypeToken<HashMap<Integer, String>>(){}.getType());
// class java.util.HashMap
System.out.println(result.getClass());
}
{
Inventory inventory = new Inventory();
inventory.map1.put(2, "cake");
inventory.map2.put(3, "donut");
final Gson gson = new GsonBuilder().create();
final String json_string = gson.toJson(inventory);
// {"map1":{"2":"cake"},"map2":{"3":"donut"}}
System.out.println(json_string);
Inventory result = gson.fromJson(json_string, Inventory.class);
// class java.util.LinkedHashMap
System.out.println(result.map1.getClass());
// class java.util.LinkedHashMap
System.out.println(result.map2.getClass());
}
}
}
答案 0 :(得分:1)
将您的字段声明为HashMap
s。如果没有这样做,您将需要使用自定义反序列化器。
但如果你正在使用Map
,为什么要关心它是LinkedHashMap
还是HashMap
?