Question

我正在尝试从查询中获取名称并通过GET方法传递每个名称，因此当点击＆＃34;回答＆＃34;排名，它将打开一个子窗口，我可以在其中找出哪个用户以及他评估了答案的值。

while($row = mysql_fetch_array($result))
{
    echo "<div class='answer'>"
        .$row['User']." has answered:
        <dl>                                    
            <dd>".$row['Answer']."</dd>"; ?>            
            <dd> 
                <form method='GET' action='votes.php' >
                    <input type="hidden" name="x" value="<?php echo $row['Answer'];?>"/>
                    <input type='submit'/>
                </form>

                    <a onclick="javascript:popUp()" > 
                        Rank: <?php echo $row['k'];?> 
                    </a>

问题是当我试图在votes.php中获得查询的答案时，它说$_GET['x']未定义？

＆＃13;

if(isset($_SESSION['email'])){
    if(isset($_GET['x'])){
        $ans = $_GET['x'];
        $query = "SELECT User, AES_DECRYPT(Vote,'usa') as l
                  FROM voting
                  WHERE Answer = '$ans'";

＆＃13;

提前致谢

通过GET方法传递一些隐藏的值

0 个答案: